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1 ppm = 1 mass part per 106 mass parts:

So 1 mg in 106 mg = 1.0*106 mg = 1.0*103 g = 1.0 kg

200 ppm = 200 mg per kg, in water 1.0 kg = 1.0 Litre

So 200 mg/L

Q: How many grams of calcium chloride needed to make 1.0 L of 200 ppm solution?

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1.47g

Lithium chloride is not transformed in calcium chloride.

1 L of water weights 1000 grams: Suppose you need X grams of calcium chloride.X grams CaCl2 / [X + 1000] grams solution = 0.35 = (35%/100%) and than solve the XX = 0.35 * (X + 1000)= 0.35X + 350X - 0.35X = 3500.65X = 350X = 350 / 0.65 = 538.46 = 538 grams of calcium chlorideAdd 538 grams of calcium chloride to 1 Litre waterand you'll getabout 1.54 kg of the 35% CaCl2 solution (this is less than 1.54 Liter!!)

2.5 molar calcium chloride

There is no chemical reaction between sod chloride solution and water, it would just dilute the sod chloride solution.

Related questions

1.47g

Take 5 grams of calcium chloride and dissolve it in 100ml of solution to get a 5% solution of calcium chloride. The standard way to make a weight-volume solution is to take grams of the dry substance in 100ml of volume.

You get salt at the bottom of the pan!

Lithium chloride is not transformed in calcium chloride.

Answering "http://wiki.answers.com/Q/How_many_grams_of_calcium_chloride_are_needed_to_produce_10_g_of_potassium_chloride"

The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.

0.50 grams of BeCl2

The sodium chloride mass needed is 292,2 g

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1 L of water weights 1000 grams: Suppose you need X grams of calcium chloride.X grams CaCl2 / [X + 1000] grams solution = 0.35 = (35%/100%) and than solve the XX = 0.35 * (X + 1000)= 0.35X + 350X - 0.35X = 3500.65X = 350X = 350 / 0.65 = 538.46 = 538 grams of calcium chlorideAdd 538 grams of calcium chloride to 1 Litre waterand you'll getabout 1.54 kg of the 35% CaCl2 solution (this is less than 1.54 Liter!!)

The mass of silver nitrate is 30,6 g.

600 mL of 0,9 % sodium chloride: 6 x 0,9 = 5,4 grams NaCl