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∙ 14y ago1 ppm = 1 mass part per 106 mass parts:
So 1 mg in 106 mg = 1.0*106 mg = 1.0*103 g = 1.0 kg
200 ppm = 200 mg per kg, in water 1.0 kg = 1.0 Litre
So 200 mg/L
Wiki User
∙ 14y agoTo make a 200 ppm (parts per million) solution, you would need 0.2 grams of calcium chloride per liter of solution. Therefore, for a 1.0 L solution, you would need 1.0 gram of calcium chloride.
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
To create a 35% solution of calcium chloride in water, you would add 350 grams of calcium chloride to 1 liter of water. This is because 35% of the final solution would be calcium chloride, and the rest would be water.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
The molar ratio between lithium chloride and calcium chloride is 2:1 in this reaction. This means that 5.5 grams of lithium chloride will produce 7.33 grams of calcium chloride.
This is from the website linked to the left of this answer under Web Links:Solubility in water, g/100 ml at 20°C: 74.5Therefore, in 1 liter, 745.0 grams of CaCl2 will dissolve to make a saturated solution.
To make a 0.01 M solution of calcium chloride, you would need to calculate the molecular weight of calcium chloride (CaCl2), which is 110.98 g/mol. Since the molarity is 0.01 M, it means there are 0.01 moles of CaCl2 in 1 liter of solution. Therefore, to make the solution, you would need 1.1098 grams of calcium chloride.
To make a 5% solution of calcium chloride with a total volume of 500 ml, you would need to add 25 grams of calcium chloride. This is calculated by multiplying the volume of the solution (500 ml) by the desired concentration (5%) and converting to grams.
You get salt at the bottom of the pan!
To create a 35% solution of calcium chloride in water, you would add 350 grams of calcium chloride to 1 liter of water. This is because 35% of the final solution would be calcium chloride, and the rest would be water.
To calculate the total amount of sodium chloride needed for a 13 L solution at 4 grams per liter, multiply the concentration by the volume of the solution: 4 grams/L x 13 L = 52 grams of sodium chloride. Therefore, you will need 52 grams of sodium chloride to make the 13 L solution.
The molar ratio between lithium chloride and calcium chloride is 2:1 in this reaction. This means that 5.5 grams of lithium chloride will produce 7.33 grams of calcium chloride.
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
To find the amount of calcium chloride needed, you would first need to determine the molar ratio between calcium chloride and potassium chloride in the chemical reaction. Then, you could use this ratio to calculate the amount of calcium chloride required to produce 10 g of potassium chloride. The molar ratio is 1:1, so the same amount of calcium chloride as potassium chloride, 10 g, would be needed.
The sodium chloride mass needed is 292,2 g
Calcium chloride contains around 36-40% elemental calcium by weight. This means that for every 100 grams of calcium chloride, there would be approximately 36-40 grams of elemental calcium. It is important to consider this when calculating the actual amount of calcium being consumed from calcium chloride supplements or additives.
The mass of silver nitrate is 30,6 g.
To find the number of chloride atoms in 654.5 grams of calcium chloride, you would first calculate the number of moles of calcium chloride using its molar mass. Then, since each formula unit of calcium chloride contains two chloride ions, you would multiply the number of moles by 2 to find the number of chloride atoms.