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How many grams of carbon are required to prepare 10 L of CO2 at STP?
Wiki User
∙ 6y ago
C + O2 ==> CO2At STP 1 mole CO2 = 22.4 L
10L x 1 mole/22.4 L = 0.446 moles CO2 needed
1 mole C = 1 mole CO2
Therefore you need 0.446 moles C
grams C = 0.446 moles C x 12 g/mole = 5.36 grams = 5 g (to 1 significant figure)
Wiki User
∙ 6y ago
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