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If 15 liters of propane are completely consumed how many grams of carbon dioxide are produced?
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
When methane is burned with oxygen the products are carbon dioxide and water If you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen how many grams of carbon dioxide were pr?
To find the grams of carbon dioxide produced, start by calculating the moles of each reactant using their molar masses. Then determine the limiting reactant (the one that forms less product). In this case, oxygen is the limiting reactant. Use the mole ratio from the balanced chemical equation to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass.
How many grams of carbon dioxide are produced when 7.5 grams of sodium carbonate reacts with nitric acid?
First write the balance equation: Na2CO3 + 2HNO3 ==> 2NaNO3 + CO2 + H2O Next calculate moles of Na2CO3 used: 7.5 g x 1 mole/106 g = 0.071 moles Na2CO3 Then look at mole ratio of Na2CO3 to CO2 and see that it is 1 to 1 Thus, moles CO2 produced = 0.071 moles Finally, convert moles CO2 to grams of CO2: 0.071 moles x 44g/mole = 3.1 g (to 2 significant figures)
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
When there are 3 grams of carbon and 8 grams of oxygen if all of the carbon and oxygen reacted how many grams of carbon dioxide are produced?
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
How many grams of carbon dioxide is produced from the combustion of B grams of hexane?
The combustion of hexane (C6H14) produces carbon dioxide (CO2) according to the reaction: C6H14 + 7O2 → 6CO2 + 7H2O. For every 1 gram of hexane burned, approximately 3.03 grams of carbon dioxide are produced. Therefore, from the combustion of B grams of hexane, the amount of carbon dioxide produced would be approximately 3.03B grams.
If 15 liters of propane are completely consumed how many grams of carbon dioxide are produced?
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
What weight and volume of carbon dioxide would be produced by burning 24 grams of carbon in air?
Weight:1.45 grams volume: 6.789
How much carbon can 22 grams of carbon dioxide make?
22 grams of carbon dioxide contains 12 grams of carbon. This amount of carbon can combine with 32 grams of oxygen to form 44 grams of carbon dioxide.
When methane is burned with oxygen the products are carbon dioxide and water If you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen how many grams of carbon dioxide were pr?
To find the grams of carbon dioxide produced, start by calculating the moles of each reactant using their molar masses. Then determine the limiting reactant (the one that forms less product). In this case, oxygen is the limiting reactant. Use the mole ratio from the balanced chemical equation to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass.
How many particles of carbon dioxide are produced if 88 grams of propane are used?
9 particles
How many moles of carbon dioxide are there in 19 grams of carbon dioxide?
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
How many grams of carbon dioxide are produced when 23.5 g of propanol react with excess oxygen in a combustion reaction?
First, calculate the moles of propanol (C3H7OH) using its molar mass. Then, use the balanced chemical equation for the combustion reaction of propanol to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass to find the mass produced.
When 3 g of carbon brunt in 50 g of oxygen then find the mass of carbon dioxide produced?
The equation for the reaction is C + O2 -> CO2. The relevant gram atomic masses are 12.011 for carbon and 15.9994 for oxygen. Therefore, the ratio of the mass of carbon dioxide produced to carbon burnt is [2(15.9994) + 12.011]/12.011 or about 3.66. From burning 3 grams of carbon, the mass of carbon dioxide produced is therefore 1 X 101 grams, to the justified number of significant digits.
How many grams of carbon dioxide are produced by the combustion of 224 liters of ethane gas CH in standard conditions?
88
