How many grams of ethanol would be formed from the reaction of 0.250 kg of glucose?

Answer 1

The conversion equation of glucose to ethanol is:

C{6}H{12}O{6} → 2C{2}H{5}OH + 2CO{2}

(Where numbers in braces {} should be in subscript which I can't do here)

Thus 1 mole of Glucose forms 2 moles of Ethanol.

1 mole of glucose weighs : 6×12 + 12×1 + 6×16 g = 180g

1 mole of ethanol weighs: 2×12 + 5×1 + 16 + 1 = 46 g

→ 180g of glucose makes 2×46 g = 92 g of ethanol

→ 0.250 kg glucose = 0.250 × 1000 g = 250 g

→ 0.250 kg glucose can produce 250 g ÷ 180 g × 92 g = 127 7/9 g ≈ 128 g of ethanol.

Answer 2

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