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To calculate the amount of iron in Fe2S3, first find the molar mass of Fe2S3: Iron (Fe) has a molar mass of 55.85 g/mol and sulfur (S) has a molar mass of 32.06 g/mol. So, the molar mass of Fe2S3 is 2(55.85) + 3(32.06) = 222.92 g/mol.
Next, divide the molar mass of iron by the molar mass of Fe2S3 and multiply by the given mass of Fe2S3 to find the grams of iron: (2 * 55.85 g/mol / 222.92 g/mol) * 34 g = 8.53 g of iron in 34 g of Fe2S3.
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How many grams of iron are in Mg of iron?
1 mg of iron is equal to 0.001 grams of iron.
How many grams of iron are in 350 Mg of iron?
There are 0.35 grams of iron in 350 mg. To convert milligrams (mg) to grams (g), you can divide by 1000.
How many grams of Fe2S3 can be formed from 17 g S and excess of Fe?
To calculate the maximum amount of Fe2S3 that can be formed, we need to determine the limiting reactant. Using the balanced equation for the reaction between Fe and S to form Fe2S3, we find that 8 moles of S react with 3 moles of Fe. From 17 g of S, we can calculate the amount of Fe2S3 that can be formed by converting the mass of S to moles and using the mole ratio from the balanced equation.
How many moles are in 1.5 grams of iron?
To find the number of moles in 1.5 grams of iron, you need to divide the mass of iron by its molar mass. The molar mass of iron is approximately 55.85 g/mol. So, 1.5 grams of iron is equal to 1.5 g / 55.85 g/mol = 0.027 moles of iron.
How many grams of iron are in 6.02 X 1023 atoms of iron?
To calculate the number of grams of iron, you need to convert the number of iron atoms (6.02 x 10^23) into moles by dividing by Avogadro's number (6.022 x 10^23 atoms/mol). Then, multiply the number of moles of iron by the molar mass of iron (55.85 g/mol) to find the grams of iron. This would result in approximately 55.85 grams of iron.
How many grams of iron can be found in a 130 g sample of iron III sulfide?
The formula of iron (III) sulfide is Fe2S3, showing that each formula unit contains two iron atoms. The gram formula unit mass for iron (III) sulfide is 207.87, and the gram atomic mass of iron is 55.847. Therefore, the fraction by mass of iron in iron (III) sulfide is 2(55.847)/207.87 or about 0.5373, and the grams of iron in 130 g of iron (III) sulfide is 0.5373 X 130 or 69.9 grams, to the justified number of significant digits.
How many grams of iron can be made form 119 g of Fe2S3 and 12.7 g C?
To determine the amount of iron that can be produced from 119 g of Fe2S3 and 12.7 g of C, we first need to calculate the molar mass of Fe2S3 and C. The molar mass of Fe2S3 is approximately 207.9 g/mol, and the molar mass of C is approximately 12.01 g/mol. Next, we calculate the moles of Fe2S3 and C by dividing the given masses by their respective molar masses. Then, we determine the limiting reactant by comparing the moles of Fe2S3 and C. Finally, we use the stoichiometry of the balanced chemical equation to calculate the theoretical yield of iron, which is approximately 42.4 grams.
How many grams are contained in 11.89 pounds?
how many grams are contained in 11.89 pounds?
How many grams are contained in 9.39410 kilograms?
9394.1 grams
How many grams contained in 11.89 pounds?
5,393.213 grams.
How many grams of iron are in Mg of iron?
1 mg of iron is equal to 0.001 grams of iron.
How many grams are contained in 192.2 mg?
192.2mg is 0.1922 grams.
How many kilograms are contained in 44.84 grams?
0,04484 kg = 44,84 grams
How many grams are contained in 31.91 centigrams?
0.3191 grams are in 31.91 centigrams.
How many kilograms are contained in 95917 grams?
95.917
How many grams are contained in 91836 milligrams?
91.836
How many kilograms are contained in 953.7 grams?
.9537
