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How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
How many grams of water are needed to react with 0.373 mol of ethylene?
To react with 0.373 mol of ethylene (C2H4), you need an equal number of moles of water (H2O) based on the balanced chemical equation: C2H4 + H2O → C2H5OH This means you need 0.373 mol of water to react with 0.373 mol of ethylene. To convert moles to grams, you would multiply 0.373 mol by the molar mass of water (18.015 g/mol) to get the grams needed.
How many grams of ethylene as needed to react with 0.0126 mole of water?
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
How many moles of nitrogen dioxide are needed to react with 5.0 moles of water?
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
How many grams of H2O are needed to react with 3.5 moles of ethylene?
63 g of water are needed.
How many grams of water are needed to react with 73.0 g CaCN2?
mass H2O =49.2g
How many grams of water are needed to react with 79.0 CaCN2?
To determine the amount of water needed to react with 79.0 CaCN2, you need to use stoichiometry. The balanced chemical equation for the reaction is: CaCN2 + 3H2O -> CaCO3 + 2NH3 From the equation, you can see that 3 moles of water are needed to react with 1 mole of CaCN2. Calculate the moles of CaCN2 in 79.0 grams, then use the mole ratio to determine the moles of water needed. Finally, convert the moles of water to grams using the molar mass of water.
How many grams of water are needed to react with 0.373 mol of ethylene?
To react with 0.373 mol of ethylene (C2H4), you need an equal number of moles of water (H2O) based on the balanced chemical equation: C2H4 + H2O → C2H5OH This means you need 0.373 mol of water to react with 0.373 mol of ethylene. To convert moles to grams, you would multiply 0.373 mol by the molar mass of water (18.015 g/mol) to get the grams needed.
How many grams of ethylene as needed to react with 0.0126 mole of water?
To determine the grams of ethylene needed to react with 0.0126 mole of water, you need to use the balanced chemical equation for the reaction between ethylene and water. Once you have the balanced equation, use the molar ratio between ethylene and water to convert moles of water to moles of ethylene. Then, use the molar mass of ethylene to convert moles of ethylene to grams of ethylene.
How many grams of are needed to react with 3.18 of?
cannot answer without more info.
How many grams of silver nitrate are needed to react with 50 grams of sodium chloride?
You need 145,337 g silver nitrate.
How many liters of water are needed to react with 2L of oxygen to make water?
Water does not need to react with oxygen to make water!
How many grams of water are needed to react with 75.0 grams of CaCN2 in CaCN2 3H2O-CaCO3 2N3?
To determine the grams of water needed to react with 75.0 grams of calcium cyanamide (CaCN₂), we first need to know the molar mass of CaCN₂, which is approximately 80.1 g/mol. The balanced chemical reaction for the formation of CaCO₃ and other products indicates that 1 mole of CaCN₂ reacts with 3 moles of water. Therefore, with 75.0 grams of CaCN₂ (about 0.9375 moles), you would need approximately 2.81 moles of water, which is about 50.6 grams (since the molar mass of water is about 18 g/mol). Thus, around 50.6 grams of water are required for the reaction.
How many moles of nitrogen dioxide are needed to react with 5.0 moles of water?
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
How many gram of water are needed to react with gram of 2.72 grams Li2O given Li2O H2O2LiOH?
The molar mass of Li2O is 29.88 g/mol and the molar mass of H2O is 18.02 g/mol. Using stoichiometry, we find that 2.72 grams of Li2O requires 2.72 grams of water to react in a 1:1 ratio based on the balanced chemical equation.
How many grams of oxygen are needed to react with 6.78 grams of ammonia?
To calculate the number of grams of oxygen needed to react with 6.78 grams of ammonia, we first write out the balanced chemical equation for the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). Then we use the stoichiometry of the equation to find the molar ratio between ammonia and oxygen. Finally, we convert the mass of ammonia to moles and then use the molar ratio to find the mass of oxygen needed.
