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How many handshakes At a business meeting of five people every person shakes hands with every other person one time. How many total handshakes occur?
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there are 3 people at a party if each person mis shake hands with every person at the party exactly once how many handshakes will there be?
So, there will be 3 handshakes among the 3 people at the party.
How many handshakes will there be altogether at the end of a business conference if the ten people present all shake hands with each other once?
There will be 45 handshakes (assuming that each person doesn't repeat who they shake hands with). Use the following formula for this one (n*(n-1))/2 where n is number of people...so if 10 people its (10 x 9) / 2 = 45 handshakes, if 7 people its (7 x 6) / 2 = 21 handshakes etc.
If there are 8 people at a party and every person shakes hands with everyone else at the party how many handshakes will there be?
There will be 28 handshakes. If you ask each person how many handshakes they had they will tell you 7 making 7 x 8 = 56 handshakes in all. But every hand involves two people, so every handshake has been counted twice, thus there are 56 / 2 = 28 handshakes in all.
There are 3 people at a party If each person must shake hands with every other person at the party exactly once how many handshakes will there be?
With 3 people, there are only 3 handshakes: AB, AC, and BC. Where it gets interesting is at a party with, say, 10 people ... 45 handshakes. Or in the US Senate when all 100 Senators are present ... 4,950 handshakes.
If at a party there are twelve people present Everyone has to shake hands exactly once with every other person How many handshakes are necessary?
Sixty-six unique, distinct handshakes.
How many handshakes if 20 people shake hands with every other person in the room?
190
There are five people in a room Each person shakes the hand of every other person exactly once How many handshakes are exchanged?
Everyone shakes hands with 4 other people. Since there are 5 people in the room this would suggest there are 5*4 = 20 handshakes. However, you would then be double counting handshakes: A shaking hands with B and B shaking hands with A is, in reality, only one handshake. Thus there are 5*4/2 = 10 handshakes in all.
How many handshakes if 25 people shake hands with every other person in room?
Each person will shake hands with every other person, except himself. If there are 25 people, each person will shake hands with 25-1 people, or 24. The number of times each person will shake hands with another, will be 25x24. The number of handshakes will be half of that, as each handshake is between two persons. The formula, in other words, is x(x-1)/2, where x is the number of people. With 25 people, it will be 25x24/2 = 300 handshakes.
How many people would you need to guarantee that there were at least 1000 handshakes?
You could never guarantee 1000 handshakes because the people may choose not to shake hands! If each person did shake hands with everyone else, then 46 people would suffice.
How many handshakes if 4 people shakes hands with every other person in the room?
Type your answer here... 6
How many handshakes for 50 people?
If each person shakes the hand of every other person just once, then 50*49/2 = 1225
At the end of a banquet 5 people shake hands with each other How many handshakes will there be in total?
Each person shakes hands with every other person at the end of the banquet. When person 1 shakes hands with person 2 that constitutes one handshake even though 2 people are involved. So the answer is 10 total handshakes because the 1st person will have 4 total handshakes(because he can't shake hands with himself, he has 4 and not 5 total handshakes), and then the 2nd person will have 3 total handshakes (you wouldn't say 4 handshakes because you've already included the handshake between person 1 & person 2 when calculating the first person's number of shakes) and so on for the remaining 3 people. On paper the math would look like this: 4+3+2+1=10 Alternatively: Each person shakes hands with 4 others so the answer looks like 5x4 = 20; However, in Fred shaking with 4 others, he shakes with Charlie, similarly, in Charlie shaking with 4 others he shakes with Fred. Thus the Fred-Charlie handshake has been counted twice (once by Fred, once by Charlie), as have all the handshakes, thus the answer is: 5x4 / 2 = 10.
