How many hydrogen atoms are present in 75.0 of g H2O?

Answer 1

The gram-molecular mass of H2O is 18.01. Therefore, 75.0 grams contains 75.0/18.01 = 4.16 moles. Each molecule contains two hydrogen atoms. Therefore, the number of hydrogen atoms = 2(4.16)(6.022 X 1023) = 5.01 X 1024 atoms.

Answer 2

There are 2 hydrogen atoms in 1 water molecule (H2O). The molar mass of water is approximately 18 g/mol, where 2 g/mol comes from hydrogen. To calculate the number of moles of water in 75.0 g, divide 75.0 g by 18 g/mol to get approximately 4.17 moles. Since there are 2 hydrogen atoms in each water molecule, there are approximately 8.33 (4.17 moles x 2) moles of hydrogen atoms.

Answer 3

Use this formula and you should be fine: n=m/M

n= number of moles

m= mass of the compound given

M= molar mass (in this case, add the mass of 2 H +O)

n(H20)= 75.0/18.02

4.16 moles

than to get the amount of water molecules in 75g

4.16 multiple by 6.02*10^23

=2.50*10^24 molecules

Answer 4

Water has a molar mass of 18.0153 grams per mole. 75 grams of the substance is then equal to 4.16 moles of water.

Answer 5

75.0 g H2O x 1 mole/17.99 g x 6.02x10^23 molecules/mole = 2.51x10^24 molecules

Answer 6

4.17 molecules

Answer 7

7.0 moles

:) welcome!

Answer 8

The answer is 4,166 moles.

Answer 9

2.51 x 10^24

Answer 10

200 miilion