There is one hydrogen atom in one formula unit of NaOH.
Sodium hydroxide is NaOH and contains three atoms, one each of sodium, hydrogen and oxygen.
hydroxide atoms
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
There are three elements represented here: sodium (Na), oxygen (O), and hydrogen (H). But while there is a such thing as NaOH, I do not belive there is a such thing as Na2OH4
sodium hydroxide is NaOH so its atomic mass is 23+1+16=40 so one mole of NaOH contains 40 grams and 6.023*10^23 molecules hence 10 grams will have 0.25 moles and hence 0.25*6.023*10^23 molecules ==1.0575 *10^23 molcules now 1 molecule of NaOH has 3 atoms so total no of atoms in 10 gram is 1.0575*3*10^23=1.592330625810^23 atoms
Sodium hydroxide is NaOH and contains three atoms, one each of sodium, hydrogen and oxygen.
hydroxide atoms
There are 3 atoms present: 1 sodium (Na), 1 oxygen (O), and 1 hydrogen (H).
The formula mass of sodium hydroxide, NaOH is 23.0+16.0+1.0=40.0 Amount of NaOH in 25.0g sample = 0.625mol
There are three elements represented here: sodium (Na), oxygen (O), and hydrogen (H). But while there is a such thing as NaOH, I do not belive there is a such thing as Na2OH4
208g NaOH
.1146g of mass of Unknown and 12.00ml of NaOH. Find the moles of acidic H atoms
sodium hydroxide is NaOH so its atomic mass is 23+1+16=40 so one mole of NaOH contains 40 grams and 6.023*10^23 molecules hence 10 grams will have 0.25 moles and hence 0.25*6.023*10^23 molecules ==1.0575 *10^23 molcules now 1 molecule of NaOH has 3 atoms so total no of atoms in 10 gram is 1.0575*3*10^23=1.592330625810^23 atoms
8 grams NaOH (1 mole NaOH/39.998 grams) = 0.2 moles NaOH
This is acetic acid which is monobasic acid so one mole of it is neutralized by one mole of NaOH.
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
This solution contain 26,3 g NaOH.