This is acetic acid which is monobasic acid so one mole of it is neutralized by one mole of NaOH.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
CH4 (methane) is the only organic molecule among the ones listed. Organic molecules are compounds that contain carbon and are typically found in living organisms. H2O, NaCl, and NaOH are inorganic compounds.
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
NaOH is Sodium Hydroxide.
To find the number of moles in 9.4 g of NaOH, you first need to calculate the molar mass of NaOH (22.99 g/mol for Na, 15.999 g/mol for O, and 1.008 g/mol for H). Add these together to get 39.997 g/mol for NaOH. Next, divide the given mass by the molar mass to get the number of moles: 9.4 g / 39.997 g/mol ≈ 0.235 moles of NaOH.
To calculate the grams of NaOH, first find the molar mass of NaOH (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H) = 40.00 g/mol. 9.03 x 10^23 molecules of NaOH is equivalent to 1 mole of NaOH. Therefore, 9.03 x 10^23 molecules of NaOH is equal to 40.00 grams.
One Mole of Sodium Hydroxide NaOH= 40.00g/l =1N (8.0g NaOH in 100.0ml of water)= 2N NaOH or (80g of NaOH in 1L of water)= 2N NaOH
When NaOH dissolves in HCl, the NaOH molecules dissociate into Na+ and OH- ions, while the HCl molecules dissociate into H+ and Cl- ions. In the solution, the OH- ions from NaOH and the H+ ions from HCl combine to form water molecules. The Na+ and Cl- ions remain in the solution.
208g NaOH
To make a 0.2 M solution of NaOH, you would need to dissolve 1 mole of NaOH in enough water to make a final volume of 1 liter. This corresponds to approximately 40 grams of NaOH.
This solution contain 26,3 g NaOH.
The number of moles of NaOH used in the titration process can be calculated by dividing the volume of NaOH solution used by the molarity of the NaOH solution.
This is an exothermic reaction, which releases heat energy as the lye (NaOH) dissolves in water. This heat is generated due to the interaction between the ions in the NaOH and the water molecules.
The number of moles is 0,0038.
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
Molarity = moles of solute/Liters of solution 3.42 M NaOH = 1.3 moles NaOH/Liters NaOH Liters NaOH = 1.3 moles NaOH/3.42 M NaOH = 0.38 Liters
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.