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The no. of IP's that can be assigned to single computer depends on the subnet mask. if the subnet mask is of A class then the IP's assigned can be 16777216. If the subnet mask is of B class then the no. of IP's that can be assigned is 65536. And if the subnet mask is of C class then the IP's assigned can be 254.
The default subnet masks per class are: class A 255.0.0.0 class B 255.255.0.0 class C 255.255.255.0
: The ISP can assign the smallest subnets to each customer, i.e., he can use subnet mask 255.255.255.248. Note: 24810= 111110002 In this way, he can assign 8 IP addresses for each customer For example, ISP assigns 193.5.48.8 to 193.5.48.15 to one customer, since 810 = 000010002, 1510 = 000011112, these IP addresses are in the same subnet using subnet mask 255.255.255.248. The customer will use 193.5.48.8 as his subnet ID and 193.5.48.15 as the local broadcasting address. He has 6 IP addresses for computers.
199.16.24.0 net mask in binary is 11111111.11111111.1111111.1110000 that means our mask bits are 1+2+4+8+16 = 31 add one for the zero address giving a total of 32 possible ip addresses 2 of which are reserved so you have 29 possible addresses for the network
Ok good question To subnet any network requires borrowing host addresses The 255.255.192.0 regardless of class says host addresses start at CIDR (Classless Inter Domain Routing Protocol) /18. So if we borrow every available host address space then we have 2^14 = 16,384 possible subnet addresses available, NOT. In reality we have 11111111.11111111.11000000.00000000 or a /18 network. Every network / subnet requires two special reserved addresses. The network or zero address, and the last address in the range which will be assigned as the broadcast address. So we can't borrow all of the bits for sub netting. If we only leave one we will only have two addresses for the hosts, this won't work because we need to reserve two. We have to leave two so we will have 2^2 = 4. We can then give each subnet a network address and a broadcast address and still have 2 usable hosts' addresses. If we do this we only have 2^12 subnets = 4096. Each subnet will only have two usable host addresses and two reserved addresses. See the math confirms that 4096 * 4 = 16384 which is the total number of addresses in the address space we started with.
In a /28 subnet, there are 16 IP addresses available. This is calculated as 2^(32-28) = 2^4 = 16. However, two of these addresses are reserved: one for the network address and one for the broadcast address. Therefore, there are 14 usable IP addresses in a /28 network.
It doesn't. It can start with almost anything, between 0.0 and 223.255. However, addresses on a local network have to start with the same few bytes (how many, depends on the subnet mask).Addresses that start with 192.168 are one range of private addresses - addresses recommended for private networks. The other private addresses are anything that starts with 10, and anything that starts with something in the range 172.16 - 172.31.It doesn't. It can start with almost anything, between 0.0 and 223.255. However, addresses on a local network have to start with the same few bytes (how many, depends on the subnet mask).Addresses that start with 192.168 are one range of private addresses - addresses recommended for private networks. The other private addresses are anything that starts with 10, and anything that starts with something in the range 172.16 - 172.31.It doesn't. It can start with almost anything, between 0.0 and 223.255. However, addresses on a local network have to start with the same few bytes (how many, depends on the subnet mask).Addresses that start with 192.168 are one range of private addresses - addresses recommended for private networks. The other private addresses are anything that starts with 10, and anything that starts with something in the range 172.16 - 172.31.It doesn't. It can start with almost anything, between 0.0 and 223.255. However, addresses on a local network have to start with the same few bytes (how many, depends on the subnet mask).Addresses that start with 192.168 are one range of private addresses - addresses recommended for private networks. The other private addresses are anything that starts with 10, and anything that starts with something in the range 172.16 - 172.31.
A unicast address is a unique IP address assigned to a single network interface, allowing for one-to-one communication. In IPv4, an unicast address falls within the ranges of 0.0.0.0 to 223.255.255.255, excluding reserved addresses. With a default subnet mask, for example, a Class A address (1.0.0.0 to 126.255.255.255) has a default mask of 255.0.0.0, Class B (128.0.0.0 to 191.255.255.255) has 255.255.0.0, and Class C (192.0.0.0 to 223.255.255.255) has 255.255.255.0. Thus, any address within these ranges is considered a unicast address when using the corresponding default subnet mask.
The subnet Mask I presume you mean.There is no single SET subnet mask for any IPThe subnet mask for most general home networks is 255.255.255.0The subnet mask is identified by the third set of numbers in the IP address when converted to binary.
How many possible host addresses are there in a Class A range?Class A range is 0 - 1270.0.0.0 and 127.0.0.0 are not "routable" IP addresses. One defines all networks and the other is the loopback. We have a total of 126 usable networks and 16,777,214 usable hostaddresses per network.
To connect devices using the IP addresses 192.168.2.1 and 192.168.1.1, you first need to ensure they are on the same subnet. This may require changing one of the IP addresses to match the subnet of the other. For example, you could change 192.168.2.1 to 192.168.1.2. Once both devices are on the same subnet, you can connect them directly via Ethernet or through a router that supports both IP ranges.
I'm not sure what you mean by Contiguous. As long as the IP's are on the same subnet it doesn't matter which one they get from the range. THe Subnet mask, Gateway and possibly DNS addresses all need to be the same but the IP can be anything from the range. Use DHCP if possible so you know all your PC get the same network configuration. If this is a subnet issue then simply set the subnet mask appropriatley for your IP range - use an online calulator if you need help doing this.