1 mole Fe = 55.845g Fe
1 mole Fe = 6.022 x 1023 atoms Fe
23.0g Fe x (1 mole Fe/55.845g Fe) x (6.022 x 1023 atoms Fe/1 mole Fe)
= 2.40 x 1023 atoms Fe
in one molecule of Fe2O3 there would be 3 oxygen atoms
Ferric sulfide has 2 Fe (iron) atoms and 3 S(sulfur) atoms. So totally 5 atoms.
2
4 oxygen atoms are present
Steel is primarily Iron and Carbon. However, other elements can be present in different alloys, such as the following:ManganeseChromiumnickelirontungstenmolybdenumborontitaniumvanadiumCobaltniobiumphosphorussulfursilicontraces of oxygen, nitrogen, and copper
The number of atoms is indicated by coefficients.
Five iron atoms have a mass of 1.3155 x 10-22 grams.
in one molecule of Fe2O3 there would be 3 oxygen atoms
The answer is 38,174.10ex.23 atoms
Iron is composed of single atoms, so 1.
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
Fe1mol Fe =2.27×1024 atoms F
Ferric sulfide has 2 Fe (iron) atoms and 3 S(sulfur) atoms. So totally 5 atoms.
0,38.1023 iron atoms
There are two atoms of iron and three atoms of oxygen in the compound Fe2O3. The mass percent of iron is 69.943%
Iron II chloride is FeCl2 and there are thus 3 atoms. Iron III Chloride is FeCl3 and ith has 4 atoms.
3.82 × 1024 Fe atoms