Fe1mol Fe =2.27×1024 atoms F
one mole of a compound contain 6.022x1023 particles(molecules) and therefor in two moles of iron there will be 2x6.022x1023 molecules.since atomic state of iron(Fe)is its molecular state,IT WILL CONTAIN 2X6.022X1023 iron atoms...
1 mole is quantify 6.022 x 10^23 atoms or molecules. It just need to multiply 0.652 with 6.022 x 10^23
how many atoms of iron are present in 0.025 molar of iron
1 molar =6.022x1023 atoms
2.1 x (6.02x1023) = 1.26x1024 iron atoms.
tera abbs
10715600000000000000000
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
481,7713432.1023 atoms
10715600000000000000000
Five iron atoms have a mass of 1.3155 x 10-22 grams.
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
5.0x10^25 * (1 mol / 6.022x10^23 atoms) = 83 moles of iron.
Molar mass of iron = 55.845g/mol (atomic weight in grams/mol) 1mol Fe atoms = 6.022 x 1023 atoms Fe 10g Fe x 1mol/55.845g x 6.022 x 1023 atoms/mol = 1.078 x 1023 atoms
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
There are 1.204 x 1023 atoms in .200 mol of Pb.
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
1.3 mol
The answer is 18,061.1023 atoms.