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How many atoms are in 13.2 grams of iron?
To calculate the number of atoms in 13.2 grams of iron, you first need to determine the molar mass of iron, which is approximately 55.85 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Therefore, there are about 4.49 x 10^22 atoms in 13.2 grams of iron.
What is the mass of 1 mole of MgSO 4?
1 Fe= 55.85 1 S= 32.07 4 O= 64.00 Molar mass= 151.5304
How many moles are in 1.01e23 F atoms?
To find the number of moles in 1.01e23 fluorine atoms, divide the given number of atoms by Avogadro's number, which is approximately 6.022e23. So, 1.01e23 F atoms / 6.022e23 atoms/mol ≈ 0.168 moles of F atoms.
How many atoms of phosphorus are in 8.90 mol of copperII phosphate?
To find the number of phosphorus atoms in 8.90 mol of copper(II) phosphate (Cu₃(PO₄)₂), we first identify that each formula unit contains 2 phosphorus (P) atoms. Thus, in 8.90 mol of copper(II) phosphate, the total number of phosphorus atoms is calculated as follows: 8.90 mol × 2 P/mol = 17.8 mol of phosphorus atoms. To convert moles to atoms, we multiply by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol): 17.8 mol × (6.022 \times 10^{23}) atoms/mol ≈ (1.07 \times 10^{24}) phosphorus atoms.
Calculate the number of atom in 13.2 mol copper?
To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.
How many atoms are in 10g of Fe?
To determine the number of atoms in 10g of Fe, you first need to calculate the number of moles of Fe using its molar mass (55.85 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in those moles of Fe. Finally, multiply the number of moles by Avogadro's number to get the total number of atoms in 10g of Fe.
Determine the number of atoms in 3.75 mol Fe?
Since a mole of a metal is generally considered to be Avogadro's Number of atoms of the metal, the answer is 3.5 times Avogadro's Number or 2.1 X 1024 atoms, to the justified number of significant digits.
How many atoms are present in 4.80 moles of Fe?
To find the number of atoms in 4.80 moles of Fe, you need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, 4.80 moles of Fe would contain: 4.80 moles x 6.022 x 10^23 atoms/mol = 2.89 x 10^24 atoms of Fe.
How many atoms of Fe are in 12.5 g Fe?
To determine the number of atoms in 12.5 g of Fe, you need to first calculate the number of moles of Fe using its molar mass (55.84 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many atoms are present in 400g Iron?
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
How many iron atoms are present in a 23.0 g iron block?
To determine the number of iron atoms in a 23.0 g iron block, you would first calculate the number of moles of iron using the molar mass of iron (55.85 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of iron to atoms.
How many moles of nitrogen atoms are present in 53.55 g of FeNO32?
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
Arrange the following from the smallest number of representative particles to the largest number of representative particles1.25x1025 atoms of Zn 3.56 mol Fe 6.78x1022 molecules of glucose?
6,78.1022 molecules of glucose 2,14388229924.1024 iron atoms 1,25.1025 zinc atoms
How many iron atoms are present in 55.845grams of Iron?
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
How many atoms are in 13.2 grams of iron?
To calculate the number of atoms in 13.2 grams of iron, you first need to determine the molar mass of iron, which is approximately 55.85 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Therefore, there are about 4.49 x 10^22 atoms in 13.2 grams of iron.
What number of Fe atoms and what amount of Fe atoms are in 500 g of Fe?
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
How many moles of iron is 5.98x1024 atoms of iron?
To find the number of moles, you need to divide the number of atoms by Avogadro's number, which is about 6.022 x 10^23 atoms/mol. So, 5.98 x 10^24 atoms of iron would be approximately 9.93 moles of iron.
