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It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
Approx 2940 Joules.
2,26 Kj are necessary
The necessary heat is 9,22 joules.
How fast the energy is provided (power, in joules/second or watts) is irrelevant, as long as not too much energy gets radiated away. What you really need to know is how much energy (in joules) is needed.
134 joules. You're very welcome for answering your question.
8.200 J
gypsum
E = mass x specific heat x Δ°T Δ°T = new temperature - original temperature where Δ°T is equal to temperature change (Celsius in this case). The specific heat of Al is 0.900 J/g°C. Before we proceed to find the quantity of heat in joules, we must first find the temperature change. To calculate the temperature change, we must subtract the original temperature from the new temperature. Δ°T = 50°C - 25°C = 25°C In order to find the quantity of heat (joules), we must multiply mass, specific heat, and the temperature change (calculated above). E = 40.0g x 0.900 J/g°C x 25°C = 900 Joules or 9.0 x 102 Joules
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules
Work done (joules) and time taken (seconds) is the information needed to calculate power in watts (joules/second).
Approx 2940 Joules.
The needed heat is 47,65 Joules.
This wall mount is not designed for plaster mounting,stud mounting is required.
10 joules per second = 10 watts
There are 1000J in a single flake!! This is also the amount of joules needed to climb an average flight of stairs!!