You get actually energy (Watts) out of a battery, not calories (which is food energy).
More to the point, how many joules can one get out of a typical 9V battery. This varies somewhat depending upon the load. At low drain currents, (2mA), a typical manganese alkaline 9V battery will provide around 16,000J over its lifetime, assuming it starts out fresh and is discharged to 1V per cell. One can squeeze out a little - not much - more if you run it down to completely dead. At a 10mA draw, you drop down below 15,000J, at 100mA, only about 12,000J. The above is based on discharge curves for Duracell MN1604
3.6 mega joules
1 Newton is 1 joule/meter.
That depends on the voltage. In general, a coulomb of charge will either gain or lose (depending on the direction) one joule of energy for every volt of potential difference. For example, if the battery has 12 V, a coulomb of charge will gain or lose 12 joules of energy when going from one terminal to the other.
The equivalent of about 6,330,000,000 joules or 6 million BTUs
4 joules = about 1 ton of coal
It is approx 3.82*10^26 Joules.
A typical nuclear plant can run continously at 600 MW, which 6 x 108 Joules per second or, per day, 5.184 x 1013 Joules.
One foot-pound of force equates to about 1.355818 joules.
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Kilo is the prefix for one thousand. So, 3,872.8 joules is 3.8728 kilojoules.