539 joules, approx.
q = [ 0.803 J/( g degrees Celsius)] ( 2 multiplied by '10 to the power of 6' grams) ( 19 degree Celsius) q = 3.1 multiplied by '10 to the power of 7' Joules
If the question is about temperature difference of 1 degree Celsius, then it equals one Kelvin.If the question is about the specific temperature of 1 degree Celsius, then it equals:1 + 273.16 = 274.16 Kelvin
23º Celsius = 73.4º Fahrenheit so the result would be -3.6º Fahrenheit, which equals -19.8º Celsius.
1 degree Fahrenheit = -17.2 degrees Celsius.
539 joules, approx.
122 degree Fahrenheit = 50 degree Celsius
-230 degree Celsius = -382 degree Fahrenheit.
47ºF = 8.3ºC
It takes 4186 joules to raise the temperature of 1 kilogram of water by 1 degree Celsius. The mass does make a difference.
the answer is: 180 degrees.
46 calories (or 192, 464 joules) for each Celsius degree.
46 calories (or 192, 464 joules) for each Celsius degree.
200K = -73.150ΒΊC
1ºC = 33.8ºF
46 calories (or 192, 464 joules) for each Celsius degree.
275 kelvin = 1.85 degree Celsius