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Joules needed to rise timperature of 2.0l of warer from 20degrees celsius to 100 degrees celsius?
To calculate the joules needed to raise the temperature of water, you can use the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. First, calculate the mass of 2.0 liters of water in grams (1 mL of water = 1g), then use the specific heat capacity of water (4.18 J/g°C) to find the total heat energy required. The final step is to calculate the joules needed using the formula, remembering that 1 calorie is equivalent to 4.18 joules.
How many joules of heat are needed to change the temp of 40 g of water?
To calculate the heat needed to change the temperature of water, you can use the specific heat capacity of water, which is 4.18 J/g°C. If you're specifying the temperature change, you would use the formula Q = m * c * ΔT, where Q is the heat energy, m is the mass of the water (40 g), c is the specific heat capacity of water, and ΔT is the temperature change.
What is the amount of heat needed to raise that temperature of 1 kilogram of water 1 degree Celsius?
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
How much energy is needed to raise the temperature of 2.0 grams of water of 5.0 Celsius?
42 J
How many joules are needed to change the temperature of 100 g of water from 20 degrees Celsius to 40 degrees celsius?
8.200 J
Approximately how many Joules of heat are needed to completely change 10.0 grams of ice to water at the melting point temperature?
To completely change 10.0 grams of ice to water at the melting point temperature, we need to calculate the heat required for the phase change from solid to liquid and the heat needed to raise the temperature of the resulting water to the melting point temperature. The heat of fusion for water is 334 J/g, so the heat needed for the phase change is 10.0 g * 334 J/g = 3340 J. The heat needed to raise the temperature of the resulting water to the melting point temperature is calculated using the specific heat capacity of water, which is 4.18 J/g°C. The temperature change is from 0°C to 0°C, so no additional heat is needed for this step. Therefore, the total heat required is 3340 J.
Joules needed to rise timperature of 2.0l of warer from 20degrees celsius to 100 degrees celsius?
To calculate the joules needed to raise the temperature of water, you can use the formula Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. First, calculate the mass of 2.0 liters of water in grams (1 mL of water = 1g), then use the specific heat capacity of water (4.18 J/g°C) to find the total heat energy required. The final step is to calculate the joules needed using the formula, remembering that 1 calorie is equivalent to 4.18 joules.
How many joules of heat are needed to change the temp of 40 g of water?
To calculate the heat needed to change the temperature of water, you can use the specific heat capacity of water, which is 4.18 J/g°C. If you're specifying the temperature change, you would use the formula Q = m * c * ΔT, where Q is the heat energy, m is the mass of the water (40 g), c is the specific heat capacity of water, and ΔT is the temperature change.
How many joules are required to boil 21.1 g of water at 100 C?
The heat required to boil water can be calculated by multiplying the mass of water (21.1 g) by the specific heat capacity of water (4.18 J/g°C) and the temperature change (100°C - initial temperature). This calculation results in 8.82 kJ or 8820 J of energy needed to boil 21.1 g of water at 100°C.
How much energy would be needed to raise the temperature of 10 kilograms of water from 273 to 373 K?
10ml's of water is equal to 10cm3 of water. 10cm3 of water has a mass of 10g. The specific heat of water is 4.134 J/K. The change in temperature is 1 degree Kelvin. Use Q=mC∆T which means Heat= (Mass)(Specific Heat)(Change in Temperature) Q= (10)(4.134)(1) Q=(10)(4.134) Q=41.34 Joules
What is the amount of heat needed to raise that temperature of 1 kilogram of water 1 degree Celsius?
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
The number of kilojoules needed to raise the temperature of 32.0 g of water from 12.0 degree centigrade to 54.0 degree centigrade is?
q(Joules) = mass * specific heat * change in temperature q = 32.0 grams H2O * 4.180 J/gC *(54.0 C - 12.0 C) = 5617.92 Joules this is, of course 5.62 kilojoules
What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
How many joules are needed to change 219.70 g of water at 72.7 C to steam at 100 C?
This value is 22,418 kJ.
How much heat in joules is needed to raise the temperature of 4.0 L of water from 0 degrees Celsius to 70.0 degrees Celsius?
It takes 4.186 Joules to heat one gram of water by 1-degree Celsius. 4.186 * 4000 = 16,744 Joules to heat 4 kilos of water by 1-degree. 16,744 * 70 = 1,172,080 Joules. The above assumes that one litre of water weighs exactly 1 Kilogram.
How much energy is needed to raise the temperature of 2.0 grams of water of 5.0 Celsius?
42 J
