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What is needed for water to change from a solid to a liquid?
A room temperature ubove 0 degrees centigrade.
How much heat is in fresh water?
It would depend on the temperature of the water, or average kinetic energy. (KE) However, what you may be looking for is how much heat is needed to raise the KE, or temperature, of water. 4.184 kilojoules per gram is the heat required to raise the temperature of water 1 degree Celsius.
What is the formula needed to convert Fahrenheit to centigrade scale?
Fahrenheit temperature minus 32, multiplied by 5, then divide by 9 to find the Centigrade/Celsius equivalent Centigrade/Celsius temperature multiplied by 9, then divide by 5, then add 32 to find the Fahrenheit equivalent
What is Joules per gram per degree centigrade?
Joules per gram per degree Celsius is a measure of specific heat capacity, which represents the amount of energy required to raise the temperature of 1 gram of a substance by 1 degree Celsius. It is a constant value unique to each substance and helps in determining how much heat energy is needed for temperature changes.
What is is the amount of heat needed to raise the temperature of one kilogram of water one degree centigrade.?
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius. To raise the temperature of one kilogram (1000 grams) of water by one degree Celsius, it would require approximately 4180 Joules of heat energy.
A pitcher containing 0.60L of water at 7C is removed from the refrigerator How many kilojoules are needed to warm the water to a room temperature of 29C?
32200
What temperature is needed for a banana tree to grow?
100 degree
What temperature switch for electric fans is needed for a 195 degree thermostat?
210
Is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.?
Yes, one calorie is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.
Time required to raise 1 degree centigrade in 1 liter of water?
To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade. The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade. The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL. 1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat. 1000g H2O *4.184J/(g*K)= 4184 J/oC Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have 4184 J/oC * 1 second/5 Joules = 836.8 s/oC This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find 836.8 s/oC *1oC = 836.8s
What is the amount of heat needed to raise that temperature of 1 kilogram of water 1 degree Celsius?
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
What is the minimum number of kiloJoules needed to change 40.0 grams of water at 100ºC to steam at the same temperature and pressure?
The heat required to change water at 100ºC to steam at the same temperature and pressure is known as the heat of vaporization. For water, this value is 40.7 kJ/mol. First, calculate the number of moles in 40.0 grams of water using the molar mass of water. Then, use this value to calculate the minimum number of kilojoules needed using the heat of vaporization.
