The answer is 55,117 kJ.
The energy needed to completely vaporize a mole of a liquid
The boiling point of ethanol is 78 C but it can evaporate slowly at just room temperature. You can set it on fire and it will vaporize even more quickly.
540 calories are needed to turn one gram of water at 100 degrees celsius to steam.
Heat of vaporization
The needed heat is 47,65 Joules.
The energy needed to completely vaporize a mole of a liquid
1oo calories for 1 g
The boiling point of ethanol is 78 C but it can evaporate slowly at just room temperature. You can set it on fire and it will vaporize even more quickly.
Gasoline has a less boiling point (72 degree Celsius) While water has a bigger boiling point (100 degree Celsius)
540 calories are needed to turn one gram of water at 100 degrees celsius to steam.
134 joules. You're very welcome for answering your question.
The boiling point is the temperature where a substance BEGINS to vaporize. So all of the water doesn't necessarily need to boil off instantly. To vaporize, molecules of water need to have energy. Only at the boiling point do they have enough energy to boil away, and when they do, they carry this energy with them. This means that a constant supply of heat for a certain period of time is needed for all water in a sample to boil off.
Heat of vaporization
Work done (joules) and time taken (seconds) is the information needed to calculate power in watts (joules/second).
Approx 2940 Joules.
The needed heat is 47,65 Joules.
The amount of energy required to turn a more of a liquid into a gas - apex