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Q=mcT

T1 = (59.4-13.4)°C = 46°C (water)->46 K

m1 = 1.93 kg

c = 4180 J/(kg x K)

T2 = (13.4-0)°C = 13.4°C (ice)->13.4 K

m2 = ?

Q1=Q2

m1 c T1=m2 c T2

m2= (m1 c T1) / (c T2) = (m1 T1) / T2 = 6.63 kg

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Q: How many kg of ice need to be added to 1.93kg of water at 59.4 degrees celsius to cool the water to 13.4 degrees celsius?
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