The code book states that the motor will draw 1.8 amps. <<>> 1 amp
100 watt
1 kilowatts = 1,000 watts 500kw=500,000w
2.3 kw per hour on a 110-120 volt circuit.
The equation that you are looking for is kW = Amps x Volts/1000. My average Sony audio amp at home uses about 20 watts or .02 kW at a low audio output level.
no
The most you could use would be 48 kW. P = E x I = 240 x 200 = 48,000 = 48 kW
The code book states that the motor will draw 1.8 amps. <<>> 1 amp
100 watt
1 kilowatts = 1,000 watts 500kw=500,000w
1 wind turbine can generate 500 houses per year (kw)
What is the KW of 4 50 amp rectifiers at a 48 volt DC system
1 kW = 1000 w So 500 W / 1000 W = 0.5 kW As soon at the heater is turned on, it starts to use energy at the rate of 500 W = 0.5 kW. If you leave it on for 10 hours it will have used up 0.5 x 10 = 5 kWh
2.3 kw per hour on a 110-120 volt circuit.
The equation that you are looking for is kW = Amps x Volts/1000. My average Sony audio amp at home uses about 20 watts or .02 kW at a low audio output level.
1 UNIT
The amount of 4 kW is equal to zero amps. To find the amperage the following equation should be used. Amps = Watts/Volts. So you can see that it depends on the voltage of the circuit if the amperage is to be found.