Need an equation as this is not familiar to me. Where is the carbon coming from? Moles? Molarity. All info I do not have.
C2h2
CaC2(s) + 2H2O(l) --> C2H2(g) + Ca(OH)2(aq) Number of moles greater than 1 are prefixes of molecule formula's. Example: '2' in 2H2O(l)
C2H2 no, isn't it H-C=C-H (the equals sign should have three lines but I don't know how do do that on the computer) C2H2 is the molecular formula, H-C=C-H is the structural formula.
yes
polar
CaC2 + 2H2O ==> C2H2 + Ca(OH)2moles of C2H2 produced = moles of Ca(OH)2 produced (1:1 mole ratio is the stoichiometry)moles of Ca(OH)2 produced = 7 g x 1mol/74.1 g = 0.0945 molesmoles C2H2 = 0.0945 molesgrams C2H2 = 0.0945 moles x 26 g/mole = 2.46 grams = 2 grams to 1 sig fig
114,426 g carbon dioxide are produced.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
2.03g C2H2
The equation for the reaction is 2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O. Therefore, the minimum mole ratio of O2 to C2H2 to permit complete reaction is 5/2. The actual ratio present, 7.40/2.40 or about 3.08, is greater than this minimum; therefore, all the available C2H2 will react. The reaction equation shows that the number of moles of H2O produced is the same as the number of moles of C2H2 reacted. Therefore, 2.40 moles of H2O are produced. The gram molecular mass of H2O is about 18.015; therefore the mass of water produced is 43.2 grams, to the justified number of significant digits.
The reaction is: 2 C2H2 + 5 O2 -------------- 4 CO2 + 2 H2O.
1.3 mole C2H2 will produce 2.6 mole CO2, weighting 2.6(mol) x 44 (g/mol) = 114 g CO2
2C2H2 + 5O2 ------------->2H2O + 4CO21 mole Of C2H2 = 26.04g, O2 = 32g, H2O = 44.01g, CO2 = 18.01g2moleC2H2 -------------> 4moleCO22x(26.04g) -------------> 4x(18.01g)52.08 g C2H2 ---------> 176.04 g CO230000g C2H2 ---------> ?? =176.04x30000g/52.08 =101405.53 gAnswer=101405.53 gram of CO2
c2h2
C2H2 (acetylene) is a linear molecule.
yep!! C2H2 is a pure subsatnce
2HCN(g) N2(g) + C2H2(g)-1.The reverse reaction rate suddenly increases. 2.C2H2 is consumed.