How many moles of CO2 are produced when 2.1 mol of C2H2
react?
CaC2 + 2H2O ==> C2H2 + Ca(OH)2moles of C2H2 produced = moles of Ca(OH)2 produced (1:1 mole ratio is the stoichiometry)moles of Ca(OH)2 produced = 7 g x 1mol/74.1 g = 0.0945 molesmoles C2H2 = 0.0945 molesgrams C2H2 = 0.0945 moles x 26 g/mole = 2.46 grams = 2 grams to 1 sig fig
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles
The balanced chemical equation for the combustion of acetylene is: 2C2H2 + 5O2 → 4CO2 + 2H2O. This means 2 moles of C2H2 produce 4 moles of CO2. Therefore, 1.3 moles of C2H2 will produce 2.6 moles of CO2, which is equivalent to approximately 84.8 grams of CO2.
The equation for the reaction is 2 C2H2 + 5 O2 -> 4 CO2 + 2 H2O. Therefore, the minimum mole ratio of O2 to C2H2 to permit complete reaction is 5/2. The actual ratio present, 7.40/2.40 or about 3.08, is greater than this minimum; therefore, all the available C2H2 will react. The reaction equation shows that the number of moles of H2O produced is the same as the number of moles of C2H2 reacted. Therefore, 2.40 moles of H2O are produced. The gram molecular mass of H2O is about 18.015; therefore the mass of water produced is 43.2 grams, to the justified number of significant digits.
When 3 moles Cu react 3 moles of copper nitrate are obtained.
The answer is 3 moles of Cu)NO3)2..
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
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The balanced chemical equation for the combustion of acetylene is: 2 C2H2 + 5 O2 → 4 CO2 + 2 H2O From the equation, 2 moles of acetylene react with 5 moles of oxygen. Therefore, 12 moles of oxygen would react with 12/5 * 2 = 4.8 moles of acetylene.
1.2 Moles
1337