As indicated by the prefix "tetra" in the compound name, each molecule of carbon tetrafluoride contains 4 fluorine atoms.
4
The carbon tetraflouride (CF4) molecule is a lone carbon atom with four singly bonded fluorine atoms around it. This means there are no free pairs of electrons available.
0 around central atom, 3 for each chlorine atom
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3
The Si has no lone pairs, but each F has 6 lone pairs. Thus 6 x 4 = 24 lone pairs, total.
In NF3, the Nitrogen atom has 5 valence electrons and each Fluorine atom shares 1 more electron with Nitrogen. That makes 8 electrons (4 pairs of electrons) around Nitrogen. Betweent the four electron pairs, 3 pairs are bonded with Fluorine and the other one is a lone pair. Therefore around the central atom Nitrogen, there are three Fluorine atoms and a lone electron pair.
3 bond pairs and no lone pairs
8
1
F-O-O-F Each oxygen has 2 lone pairs on it, while each fluorine has 3 lone pairs. Because of the 3 lone pairs on each oxygen, the bonding angles present are 109.5°.
The Si has no lone pairs, but each F has 6 lone pairs. Thus 6 x 4 = 24 lone pairs, total.
3 Lone pairs and one unpaired electron
Three bonds and no lone pairs.
One
No lone pairs
F-F So, you have 7 valance electrons apiece in fluorine, a total of 14. The bond accounts for two electrons as it is covalent. 14 - 2 = 12 There will be three lone pairs arranged around each fluorine, a total os six lone pairs.
In NF3, the Nitrogen atom has 5 valence electrons and each Fluorine atom shares 1 more electron with Nitrogen. That makes 8 electrons (4 pairs of electrons) around Nitrogen. Betweent the four electron pairs, 3 pairs are bonded with Fluorine and the other one is a lone pair. Therefore around the central atom Nitrogen, there are three Fluorine atoms and a lone electron pair.
The lone pairs are on the bromine atom- 3 in all.
3 bond pairs and no lone pairs
two bonds and eight lone pairs
Two lone pair