0
What else can I help you with?
How many address lines can access a 16MB memory?
for 16 MB memory has 24 address lines
How many nuMBer of address lines required for 8 MB of memory?
It takes 23 address lines to address 8 mb of memory.
How many memory locations can be accessed using 14 address lines?
168
How many memory locations can be addressed by a microprocessor with 14 address lines?
2^14 memory locations. In general for n-bit address bus, its 2^n
How many memory location can be address by microprocessor with 14 address line?
You can address 214 or 16384 different locations with 14 address lines.
How many hexadecimal digits are used to locate an address in the memory?
depends on the depth of memory, N address lines can map 2 Power N locations.
A microprocessor has 24 parallel address lines How many memory locations can the processor address?
32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;
How many address lines in 8088?
The Intel 8088 microprocessor has 20 address lines. This allows it to address up to 1 MB (2^20 bytes) of memory. The address lines are labeled A0 to A19, enabling the microprocessor to access a wide range of memory locations.
How many nuMBer of address lines required for 1 MB memory?
Firstly we need to convert Mb's into bits i.e 1Mb=1024x1024 = 210x210 =220 That means there are 220 memory locations and we will need 20 address lines.
How many address lines and data lines are required for a2Kx8 memory?
A 2K X 8 memory requires 11 address lines and 8 data lines
How many address lines in Pic16F877A microcontroller?
The PIC16F877A microcontroller has 13 address lines, which allows it to address 8K words of program memory. This enables it to access a range of memory locations for storing instructions. Additionally, it has 368 bytes of data RAM and 256 bytes of Electrically Erasable Programmable Read-Only Memory (EEPROM) for data storage.
How many address lines are needed to access 256KB of main memory?
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
