216 = 65536
for 16 MB memory has 24 address lines
It takes 23 address lines to address 8 mb of memory.
168
2^14 memory locations. In general for n-bit address bus, its 2^n
You can address 214 or 16384 different locations with 14 address lines.
depends on the depth of memory, N address lines can map 2 Power N locations.
32 bit address line can access 4GB of memory. As 2^10 -> 1KB; 2^20 -> 2MB; 2^30 -> 1GB and so on.... 32 bit gives (2^30) * (2^2) = 1GB * 4 = 4GB;
The Intel 8088 microprocessor has 20 address lines. This allows it to address up to 1 MB (2^20 bytes) of memory. The address lines are labeled A0 to A19, enabling the microprocessor to access a wide range of memory locations.
A 2K X 8 memory requires 11 address lines and 8 data lines
Firstly we need to convert Mb's into bits i.e 1Mb=1024x1024 = 210x210 =220 That means there are 220 memory locations and we will need 20 address lines.
The PIC16F877A microcontroller has 13 address lines, which allows it to address 8K words of program memory. This enables it to access a range of memory locations for storing instructions. Additionally, it has 368 bytes of data RAM and 256 bytes of Electrically Erasable Programmable Read-Only Memory (EEPROM) for data storage.
A 14 bit address can specify 214 or 16,384 different locations.