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1 mole of MgCl2=95.21 grams (found on the Periodic Table)
17.5 g of MgCl2(1mole of MgCl2/95.21g of MgCl2)=.184 moles of MgCl2(grams cancel out and rounded to 3 sig. figs)
.184 moles of MgCl2 (1 Liter/2.5 moles of MgCl2)=0.735L of MgCl2 (moles cancel and rounded to 3 sig figs)
0.735 L of MgCl2(1000 milliLiters/1 Liter)=73.5 mL of MgCl2 and round the answer to 2 sig figs which equals 74 milliLitersof MgCl2
Wiki User
∙ 12y ago
Wiki User
∙ 11y agoWe can see that the molar mass of MgCl2 is 24.31+2(35.34)=95.21. Therefore, 17.5 grams of MgCl2 is equal to 17.5/95.21=0.184 mols of MgCl2. Since a 2.5 M solution of MgCl2 contains 2.5 mols of MgCl2 per liter, you can set up a simple ratio as follows:
2.5 mols/1 liter = 0.184 mols/x liters
Solving for x, you see that it equals 0.184/2.5=0.0736 liters. This is also equal to 73.6 milliliters.
Wiki User
∙ 14y ago617.5g MgCl2/95.21g = 6.486 moles MgCl2
Molarity = moles of solute/volume of solution
Wiki User
∙ 10y agoThis cannot be sensibly answered. A milliliter (mL or ml) is a measure of volume, grams (g), kilograms (kg) and milligrams (mg) are measures of weight or mass.
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