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1 mole of MgCl2=95.21 grams (found on the Periodic Table)

17.5 g of MgCl2(1mole of MgCl2/95.21g of MgCl2)=.184 moles of MgCl2(grams cancel out and rounded to 3 sig. figs)

.184 moles of MgCl2 (1 Liter/2.5 moles of MgCl2)=0.735L of MgCl2 (moles cancel and rounded to 3 sig figs)

0.735 L of MgCl2(1000 milliLiters/1 Liter)=73.5 mL of MgCl2 and round the answer to 2 sig figs which equals 74 milliLitersof MgCl2

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