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3 mls = 3/5th of a teaspoon (since 5 ml = 1 tsp).
Wiki User
∙ 13y ago
Wiki User
∙ 14y agoMilliliter is a unit of volume, meters is a unit of length. You can't compare that.
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How many mL of a 0.400 M concentrated solution must be added to water to get a more dilute solution with a total volume of 10.0 mL and a new concentration of 0.160 M?
V1*c1=V2*c2 so: V1 = 10.0(mL) * 0.160 (M) / 0.400 (M) = 4.00 mL Add about 6 mL water up to the end volume of 10.0 mL
If 20.0 mL of 150 M NaOH are used in a titration how many moles of NaOH are used?
150 M NaOH = 150 mole / liter 20.0 mL = 0.0200 L 150 * 0.0200 = 3 moles
How many ml of 110 M of HCl are needed to completely neutralize 54ml of 106 M of BaOH2 solution?
A concentration of 110 M or 106 M doesn't exist.
How many gmL are there in 1 kgm3?
There are 1 g/mL in 1 kg/m^3. This is because 1 kg/m^3 is equivalent to 1000 g/L, and since 1 L is equal to 1,000 mL, 1000 g/L is equivalent to 1 g/mL.
What is the density of the acid in a car battery if 200 mL of the acid had a mass of 240g?
density = mass / volume Given mass = 240 g = 240*10^-3 kg volume = 200 mL = 200*10^-6 m^3 Hence density = 1.2*10^3 kg/m^3 Or 1200 kg/m^3
How many millimeters are in a cubic meter?
1 m^3*[(1000ml)^3/(1m^3)]=1*10^9 ml^3
How many mL of 12.1 M is required to make a 250 mL 0.1 M HCl solution?
To make a 250 mL 0.1 M HCl solution, you will need to dilute the 12.1 M solution. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration, and V2 is the final volume. Plugging in the values, you would need to add approximately 20.7 mL of the 12.1 M HCl solution to make the 0.1 M HCl solution.
How many millilitre in 1 cubic meter?
1,000,000 millilitres-------------------Solution Method:-------------------1 m = 100 cm1 cm^3 = 1 mLTherefore:"a cubic metre" = 1 m * 1 m * 1 m = 100 cm * 100 cm * 100 cm1 m^3 = 1,000,000 cm^3Convert cm^3 to mL using the conversion ratio 1 mL = 1 cm^3 as follows:1,000,000 cm^3 * (1 mL / 1 cm^3) = 1,000,000 mL(Note: cm^3 cancel)We then subsitute 1,000,000 cm^3 in the original quation with 1,000,000 mL as follows:1 m^3 = 1,000,000 mL^ This means:1 cubic metre = 1,000,000 millilitres========First Answer:========They are not equivalent. One is to measure distance/length and the other is for volume.
How many liters in a cubic metre?
Look, 1cm3=1ml If you know this you can find the others such as 1m3 This is how.. 1cm3=1ml but 1m3=1000000 cm3 therefore, 1/1000000m3=1ml therefore,1m3=1000000ml i.e.1m3=1000000/1000 litre =1000 litres got it?? ====== 1 m = 100 cm 1 cm^3 = 1 mL 1 L = 1,000 mL Therefore: "a cubic metre" = 1 m * 1 m * 1 m = 100 cm * 100 cm * 100 cm 1 m^3 = 1,000,000 cm^3 (since 1 mL = 1 cm^3, we get the following) 1 m^3 = 1,000,000 cm^3 * (1 mL / 1 cm^3) (Note: cm^3 cancel) 1 m^3 = 1,000,000 mL 1 m^3 = 1,000,000 mL * (1 L / 1,000 mL) (Note: mL cancel) 1 m^3 = 1,000 L ^ This means: 1 cubic metre = 1,000 liters
How about prepare a solution of a 0.1N acetate buffer?
The following table is extracted from the Internet:* For pH=3: mix 982,3 mL 0,1 M acetic acid with 17,7 mL 0,1 M sodium acetate* For pH=4: mix 847,0 mL 0,1 M acetic acid with 153 mL 0,1 M sodium acetate* For pH=5: mix 357 mL 0,1 M acetic acid with 643 mL 0,1 M sodium acetate* For pH=3: mix 52,2 mL 0,1 M acetic acid with 947,8 mL 0,1 M sodium acetate
You want to make a 275.0 mL of a 0.15 M solution of HCl. How many mL of a 6.0 M solution do you need?
The volume is 6,875 mL (approx. 6,9 mL).
How many mL of a 0.400 M concentrated solution must be added to water to get a more dilute solution with a total volume of 10.0 mL and a new concentration of 0.160 M?
V1*c1=V2*c2 so: V1 = 10.0(mL) * 0.160 (M) / 0.400 (M) = 4.00 mL Add about 6 mL water up to the end volume of 10.0 mL
How many ml of 250 M NaOH are required to neutralize 30.4 ml of 152 M HCl?
To neutralize the acid, we need to use the same number of moles of base. First, calculate the number of moles of HCl using its concentration and volume. Then, use the mole ratio from the balanced equation to find the required volume of NaOH. Convert the volume to mL.
How many ml of 0.10 m naoh solution are needed to neutralize 15 ml of 0.20 m h3po4 solution?
Since each molecule of H3PO4 neutralizes three molecules of NaOH, you would need 45 mL of 0.10 M NaOH solution to neutralize 15 mL of 0.20 M H3PO4 solution.
How many cubic mm in 250mL?
1 m**3 = 1000L 1000 000 000 mm**3 = 1000L 1000 000 000 mm**3 = 1000 000 mL 1000 mm**3 = 1 mL 250 000 mm**3 = 250 mL
If 20.0 mL of 150 M NaOH are used in a titration how many moles of NaOH are used?
150 M NaOH = 150 mole / liter 20.0 mL = 0.0200 L 150 * 0.0200 = 3 moles
How many mL of 0.55 M NaOH would be required to reach the equivalence point for 25.0 mL of a 0.75 M solution of acetic acid?
34.1 ml
