The volume is 6,875 mL (approx. 6,9 mL).
You need 1,25 moles ammonia.
1.25 moles of Lithium Chloride
Nope
You need 0,5 L.
If this is .020m solution, you need 3.81g If this is .20m solution, you need 38.1g If this is 20m solution, you need 3810g
For a 10 % solution you need 250 g KCl.
You need 6,9 mL stock solution.
Proportionally you will need 1 and 1/2 mg of salt.
MW 74.5, 1M solution requires 74.5g in 1L, 5M solution requires 74.5x5 = 372.5g in 1 L. You would need 93.1g KCL to make 250mL 5M solution
The Molecular Weight of NaCl = 58.5 So to make 1L of 4M NaCl solution you need 4*58.5=234g of NaCl So to make 100mL of the above solution you need 23.4 grams of NaCl
To make a 10% sugar solution you need to dissolve 10 grams of sugar and bring the volume up to 100 ml
This depends on the desired concentration of salt.
solvent and solute
You need 1,25 moles ammonia.
That completely depends on how much solution you need to end up with.If the solution is to be 1,000 ppm by weight (or mass), then you add 1 gramof KCl to each liter of water.
100ppm means, you need 100mg in 1oooml. Thus, for 100ml solution, you will need 10mg of methanol to make 100ppm solution.
1.25 moles of Lithium Chloride