There are 24 mol of P atoms in 96 mol of P4O10. This is because each P4O10 molecule contains 4 P atoms, so you need to divide the total moles of P4O10 by 4 to find the moles of P atoms.
P4O10 - P for Phosphorous, 4 for tetra; O for oxygen, 10 for dec-.
P4O4 is not a chemical compound. P4O10 is a covalent compound. P and O always form covalent bonds.
The chemical formula for Tetraphosphorus decaoxide is P4O10. The empirical formula is derived from the chemical formula by making the subscripts as low as possible while keeping all subscripts as integers. Therefore, the empirical formula from P4O10 is found by dividing both by two. The answer is P2O5.
58.1g [Ca(PO4)] X 1 mol [Ca(PO4)] X 2 mol (PO4) X 1 mol (P) X 30.97g (P) = 11.6g (P) 310.2g [Ca(PO4)] 1 mol[Ca(PO4)] 1 mol (PO4) 1 mol (P) Sorry about the formatting, im trying to show stoichiometry.
To find the mass of 5.1 mol of phosphorus (P), you need to know the molar mass of phosphorus. The molar mass of phosphorus is approximately 30.97 grams per mole. Therefore, the mass of 5.1 mol of phosphorus is 5.1 mol x 30.97 g/mol = 157.647 g.
To solve this, you need to use the mole ratio derived from the chemical formula, P4O10, and you need the molar mass of P. 3.25 mol P4O10 x 4 mol P x 30.97 g P = 403 g P .......................1 mol P4O10 1 mol P
There are 73.5 moles of P4O10 per kg of solution. Each P4O10 molecule weighs approximately 283.88 g. P makes up 123.88 or about 77.43% of this. 73.5 moles of P4O10 weighs about 20865.18 g. 77.43% of 20865.18g is 16155.91 g. Multiply this by the inverse of the molar mass of P (30.97g /mol) and your answer should be approximately 521.66 moles of P.
We first calculate the molar mass of P4O10, which is 284 g/mol. Then we convert the given mass of P4O10 (142 g) to moles using its molar mass. There is a 1:4 molar ratio between P4O10 and O2 in the reaction, so we multiply the moles of P4O10 by 4 to find the moles of O2 needed.
4p+5o2->p4o10
4p+5o2->p4o10
The correct chemical formula should be P2O5 or P4O10 (its dimer) and not P3O10 (as originally asked in the question). The oxidation numbers are -2 for each O +5 for each P
P4O10 - P for Phosphorous, 4 for tetra; O for oxygen, 10 for dec-.
One molecule of P2O3 = 1 mole. Go to the periodic table P = 30gm x 2 = 60 gm. O= 16 gm x 3 = 48 mg. Total is 60 + 48 = 108 gm is the weight of one molecule which is also the number of grams in 1 mole (remember 1 mol = 1 mole). So since you have 37.9 grams divide this by 108 and you have .35 moles.
P4O4 is not a chemical compound. P4O10 is a covalent compound. P and O always form covalent bonds.
The chemical formula for Tetraphosphorus decaoxide is P4O10. The empirical formula is derived from the chemical formula by making the subscripts as low as possible while keeping all subscripts as integers. Therefore, the empirical formula from P4O10 is found by dividing both by two. The answer is P2O5.
1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
The molar mass of P in tetraphosphorus hexaoxide is 30.97 g/mol, and the molar mass of the compound is 284.95 g/mol. Therefore, the mass fraction of P in tetraphosphorus hexaoxide is (4 mol x 30.97 g/mol) / 284.95 g = 0.438 or 43.8%.