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How many grams of H3PO4 are produced when 10.0 moles of water react with an excess of P4O10?
1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. Therefore, 10.0 moles of water will produce (10/6)*4 moles of H3PO4. To convert moles to grams, multiply the number of moles by the molar mass of H3PO4.
How many grams of ccl4 are needed to have 5.000 mol?
To find the grams of CCl4 needed, multiply the number of moles (5.000 mol) by the molar mass of CCl4 (153.82 g/mol). (5.000 , \text{mol} \times 153.82 , \text{g/mol} = 769.1 , \text{g}) Therefore, 769.1 grams of CCl4 are needed.
How many grams of H2 are needed to produce 13.14g of NH3?
To calculate the mass of H2 needed to produce 13.14g of NH3, you can use the molar ratio between H2 and NH3. From the balanced chemical equation for the reaction, you can see that 2 moles of NH3 are produced for every 3 moles of H2 consumed. First, calculate the number of moles of NH3 using its molar mass, then use the molar ratio to find the moles of H2 needed, and finally convert the moles of H2 into grams.
How many grams are in 4.72 kilograms?
There are 4720 grams in 4.72 kilograms. This conversion is done by multiplying the number of kilograms by 1000 to get the equivalent number of grams.
What is the number of grams in 5.8 kilograms?
There are 5800 grams in 5.8 kilograms, as there are 1000 grams in 1 kilogram.
How many grams of H3PO4 are produced when 10.0 moles of water react with an excess of P4O10?
1 mole of P4O10 reacts with 6 moles of water to produce 4 moles of H3PO4. Therefore, 10.0 moles of water will produce (10/6)*4 moles of H3PO4. To convert moles to grams, multiply the number of moles by the molar mass of H3PO4.
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
Stoichiometry grams of N2 are needed to produce 20 grams NH3 N2 plus H2 NH3?
16,45 g nitrogen are needed.
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many grams of potassium iodide will produce 750 grams of silver iodide when there is an excess of silver nitrate?
530,3 g potassium iodide are needed.
When 31 grams of phosphorous reacts with oxygen 71 grams of an oxide phosphorus is the product. What mass of oxygen is needed to produce 13 grams of this product?
To find the mass of oxygen needed to produce 13 grams of the oxide, we first find the molar ratio between P and O in the product. Then, use this ratio to calculate the mass of oxygen needed. Since 71g of the oxide contains 31g of phosphorus, we can calculate the mass of oxygen needed for 13g of the oxide by setting up a proportion.
When moving from grams to kilo grams do the numerical value increase?
No. Just the opposite. Every kilogram is a package of 1,000 grams. So naturally, if you pack all of your grams into packages of 1,000, your large number of grams will produce a smaller number of kilogram-packages.
How many grams of N2 must react to form 1.7 grams of ammonia NH3?
To find out how many grams of N2 are needed to produce 1.7 grams of NH3, you need to look at the balanced chemical equation for the reaction. For the reaction N2 + 3H2 -> 2NH3, the molar ratio of N2 to NH3 is 1:2. So you would need half the number of grams of N2 as NH3, which is 0.85 grams of N2.
How many grams of ccl4 are needed to have 5.000 mol?
To find the grams of CCl4 needed, multiply the number of moles (5.000 mol) by the molar mass of CCl4 (153.82 g/mol). (5.000 , \text{mol} \times 153.82 , \text{g/mol} = 769.1 , \text{g}) Therefore, 769.1 grams of CCl4 are needed.
