Divide 96 by molecular mass.So the answer is 6mol
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
For the reaction CO2 + 4H2 -> CH4 + 2H2O, the stoichiometry shows that 1 mole of CO2 produces 1 mole of CH4. Therefore, 25.1 moles of CO2 would produce 25.1 moles of CH4.
In 0.86 moles of CH4, you have 5.16 x 10^23 atoms of hydrogen. This is because there are four hydrogen atoms in one molecule of CH4, making a total of 0.86 x 4 = 3.44 moles of hydrogen atoms, which can be converted to atoms using Avogadro's number.
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
There are 0.75 moles in it.You have to devide 12 by molecular mass
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
CH4 --> CO2 is a 1 to 1 reaction (C-balanced) when burning with oxygen. So 1 mole CH4 --> 1 mole CO2 So 1 Litere CH4 --> 1 Liter CO2 So 16 grams CH4 --> 44 grams CO2
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
1,25 grams of CH4 contain 0,156696.10e23 atoms.
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
At STP (standard temperature and pressure), one mole of any gas occupies 22.4 liters. This means that 144 liters of methane gas contain 144/22.4 moles of CH4. Using the molar mass of CH4 (16 g/mol), you can calculate the mass of methane gas in grams.
The molar mass of methane (CH4) is approximately 16.04 grams per mole.
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
16 grams per mole. Methane is CH4. Look at the Periodic table: Carbon is 12 grams/mole and Hydrogen is 1 gram/mole, so 1*12 + 4*1 = 16.