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16 grams per mole. Methane is CH4. Look at the Periodic Table: Carbon is 12 grams/mole and Hydrogen is 1 gram/mole, so 1*12 + 4*1 = 16.
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What number would you use to convert moles of CH4 to grams of CH4?
To convert moles of CH4 (methane) to grams, you would use the molar mass of CH4, which is approximately 16.04 g/mol. Multiply the number of moles of CH4 by this molar mass to obtain the mass in grams. The formula is: grams of CH4 = moles of CH4 × 16.04 g/mol.
What is the atomic mass in grams of 0.35 moles of CH4?
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
How many electron are present in 1.6g of methane?
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
How many liters of water vapor at STP are produced by the combustion of 12.0g of methane?
To determine the liters of water vapor produced by the combustion of 12.0 g of methane (CH₄), we first calculate the moles of methane using its molar mass (approximately 16.04 g/mol). The balanced equation for the combustion of methane is: CH₄ + 2 O₂ → CO₂ + 2 H₂O. Thus, 1 mole of methane produces 2 moles of water vapor. Therefore, 12.0 g of methane corresponds to about 0.748 moles, resulting in approximately 1.496 moles of water vapor, which at STP (22.4 L/mol) corresponds to roughly 33.5 liters of water vapor.
How many moles of methane are there in 8.02 g of methane?
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
How many moles are in 0.289 g of methane?
To find the number of moles in 0.289 g of methane, first calculate the molar mass of methane (CH4), which is approximately 16 g/mol. Next, divide the given mass (0.289 g) by the molar mass to obtain the number of moles. Therefore, 0.289 g of methane is equivalent to 0.289 g / 16 g/mol ≈ 0.018 moles of methane.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
To calculate the mass of four moles of methane (CH4), we first need to determine the molar mass of methane. The molar mass of CH4 is the sum of the atomic masses of carbon (12.01 g/mol) and hydrogen (1.008 g/mol) multiplied by the number of atoms in the compound. Therefore, the molar mass of CH4 is 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol. To find the mass of four moles of methane, we multiply the molar mass by the number of moles: 16.04 g/mol x 4 mol = 64.16 grams. Therefore, four moles of methane would have a mass of 64.16 grams.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
How many grams Four moles of methane would have a mass of how many grams?
2344222.445
The formula for methane is CH4 Four moles of methanes would have a mass of?
The molar mass of methane (CH4) is 16 g/mol. Therefore, four moles of methane would have a mass of 64 grams.
How many moles of hydrogen are present in 3 moles of methane?
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
How many moles of water are associated with each mole of methane hydrate if a sample has 160cm3 methane and 1000g of water ar room temperature and pressure?
For each mole of methane hydrate, there are 5.75 moles of water associated with it. In this case, since you have 160 cm³ of methane and 1000g of water, we first convert 160 cm³ of methane to moles, which is 5.62 moles. Then we calculate the moles of water based on the ratio 1:5.75 for methane to water in methane hydrate, which gives us approximately 32.3 moles of water associated with the 5.62 moles of methane.
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
The equation for the reaction between methane (CH4) and oxygen is: CH4 + 2O2 → CO2 + 2H2O From the previous information, if 25.9 grams of water vapor were formed, this corresponds to 25.9 grams ÷ 18.0 g/mol = 1.44 moles of water. This means 0.72 moles of methane reacted. If the molar mass of methane is 16.0 g/mol, then 0.72 moles of methane corresponds to 0.72 moles × 16.0 g/mol = 11.52 grams of methane reacted with oxygen.
What is the atomic mass in grams of 0.35 moles of CH4?
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
What mass of water is produced from the complete combustion of 2.50x10-3 of methane?
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
How many moles of carbon dioxide are formed from 14 moles of methane?
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
