Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
The complete combustion of methane proceeds according to the equation: CH4 + 2 O2 = CO2 + 2 H2O. Therefore, each mole of methane produces two moles of water and 4 moles of methane will produce eight moles of water.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.6 liters of methane is equal to 5.6/22.4 = 0.25 moles of methane.
In 1 mole of water (H2O), there are 2 moles of hydrogen (H). This means that in 2.08 moles of water, there are 2.08 x 2 = 4.16 moles of hydrogen. To convert moles to grams, we use the molar mass of hydrogen: 4.16 moles x 1.01 g/mol = 4.22 grams of hydrogen.
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
There are 67.2 grams of hydrogen in 5.60 moles of methane. Methane (CH4) has one carbon atom and four hydrogen atoms, so the molar mass of CH4 is 16 grams/mol (carbon) + 4 grams/mol (hydrogen) = 20 grams/mol. In 5.60 moles of CH4, there are 5.60 moles x 4 mol of hydrogen/mol of CH4 = 22.4 moles of hydrogen. Finally, converting moles to grams, 22.4 moles x 1 gram/mol = 67.2 grams of hydrogen.
The complete combustion of methane proceeds according to the equation: CH4 + 2 O2 = CO2 + 2 H2O. Therefore, each mole of methane produces two moles of water and 4 moles of methane will produce eight moles of water.
To determine how many moles of methane are produced from 71.1 moles of carbon dioxide gas, we need to consider the balanced chemical reaction for the production of methane (CH₄) from carbon dioxide (CO₂) and hydrogen (H₂): [ CO₂ + 4H₂ → CH₄ + 2H₂O ] From the reaction, 1 mole of CO₂ produces 1 mole of CH₄. Therefore, 71.1 moles of CO₂ would produce 71.1 moles of methane.
At STP (standard temperature and pressure), 1 mole of any gas occupies 22.4 liters. Therefore, 5.6 liters of methane is equal to 5.6/22.4 = 0.25 moles of methane.
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
In 1 mole of water (H2O), there are 2 moles of hydrogen (H). This means that in 2.08 moles of water, there are 2.08 x 2 = 4.16 moles of hydrogen. To convert moles to grams, we use the molar mass of hydrogen: 4.16 moles x 1.01 g/mol = 4.22 grams of hydrogen.
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
One molecule has four H atoms.So two moles have 8 moles
0.25 moles
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
To produce 1 mole of methane (CH4), you need 2 moles of hydrogen (H2). Since 22.4 L of hydrogen is equivalent to 1 mole at standard temperature and pressure (STP), you would need 44.8 L of hydrogen to produce 1 mole of methane. Therefore, to produce 20 L of methane, you would need 896 L of hydrogen.
To determine how many moles of CH4 (methane) are produced along with 11 moles of water, we need the balanced chemical equation for the reaction. In the case of methane production from a reaction like the one involving carbon dioxide and hydrogen (CO2 + 4H2 → CH4 + 2H2O), every mole of CH4 produced yields 2 moles of water. Therefore, if you have 11 moles of water, you would produce 5.5 moles of CH4.