0
What else can I help you with?
How many moles of methane are there in 8.02 g of methane?
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
The equation for the reaction between methane (CH4) and oxygen is: CH4 + 2O2 → CO2 + 2H2O From the previous information, if 25.9 grams of water vapor were formed, this corresponds to 25.9 grams ÷ 18.0 g/mol = 1.44 moles of water. This means 0.72 moles of methane reacted. If the molar mass of methane is 16.0 g/mol, then 0.72 moles of methane corresponds to 0.72 moles × 16.0 g/mol = 11.52 grams of methane reacted with oxygen.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
To calculate the mass of four moles of methane (CH4), we first need to determine the molar mass of methane. The molar mass of CH4 is the sum of the atomic masses of carbon (12.01 g/mol) and hydrogen (1.008 g/mol) multiplied by the number of atoms in the compound. Therefore, the molar mass of CH4 is 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol. To find the mass of four moles of methane, we multiply the molar mass by the number of moles: 16.04 g/mol x 4 mol = 64.16 grams. Therefore, four moles of methane would have a mass of 64.16 grams.
How many liters of oxygen are needed to exactly react with 27.8 g of methane at STP?
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
How many moles of methane are there in 8.02 g of methane?
To find the number of moles of methane in 8.02 g, you need to divide the given mass by the molar mass of methane (16.04 g/mol). 8.02 g / 16.04 g/mol = 0.500 moles of methane
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
If in the previous problem only 25.9 grams of water vapor were formed how much methane actually reacted with oxygen?
The equation for the reaction between methane (CH4) and oxygen is: CH4 + 2O2 → CO2 + 2H2O From the previous information, if 25.9 grams of water vapor were formed, this corresponds to 25.9 grams ÷ 18.0 g/mol = 1.44 moles of water. This means 0.72 moles of methane reacted. If the molar mass of methane is 16.0 g/mol, then 0.72 moles of methane corresponds to 0.72 moles × 16.0 g/mol = 11.52 grams of methane reacted with oxygen.
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
To calculate the mass of four moles of methane (CH4), we first need to determine the molar mass of methane. The molar mass of CH4 is the sum of the atomic masses of carbon (12.01 g/mol) and hydrogen (1.008 g/mol) multiplied by the number of atoms in the compound. Therefore, the molar mass of CH4 is 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol. To find the mass of four moles of methane, we multiply the molar mass by the number of moles: 16.04 g/mol x 4 mol = 64.16 grams. Therefore, four moles of methane would have a mass of 64.16 grams.
How many liters of oxygen are needed to exactly react with 27.8 g of methane at STP?
1) First find the number of moles of methane in 27.8 g using the molar mass.See the Related Question to the left of this answer "How do you convert from grams to moles and also from moles to grams?" to do that.2) Then write the balanced reaction. Methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). See the related question "How do you balance a chemical reaction?" to do that.3) That will tell you the ratio of moles of methane to moles of oxygen (it will be 2 to 1). So from Part 1, multiply the number of moles of methane by 2 to get moles of oxygen. Then, use the Ideal Gas Law to find out how many liters that will take up at STP. Use the Related Question link "How do you solve Ideal Gas Law problems?" to do that.
What are the steps needed to convert 77.2 grams of methane to molecules of methane. Please wrote them out ( indluding tchart)?
Step1: Find molar mass of methane, CH4. C=12; H=1; 12+1+1+1+1 = 16 g/moleStep2: Convert grams to moles. 77.2 g x 1 mole/16 g = 4.825 moles methaneStep3: Convert moles to molecules using Avogadro's number.4.825 moles x 6.02x10^23 molecules/mole = 2.90x10^24 moleculesUnfortunately, I don't know what a tchart is, so I didn't include it.
How many molecules in 10 grams of methane?
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
What mass of water is produced from the complete combustion of 2.50x10-3 of methane?
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles of methane are required to produce 22g of CO2?
The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This means that for every mole of CH4 that reacts, one mole of CO2 is produced. The molar mass of CO2 is about 44g/mol, so 22g CO2 is equivalent to 0.5 moles. Therefore, 0.5 moles of CH4 are required to produce 22g of CO2.
How many moles are in 14.84 g Mg?
14,84 g magnesium are equivalent to 0,61 moles.
How many moles are in 97.5 g of oxygen?
97,5 g of oxygen is equal to 5,416 moles.
