First divide 1 by molecular mass 16.then multiply by Avagadro number
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
To find the number of ammonia molecules in 3.75g of CH4, you first need to convert 3.75g of CH4 to moles using the molar mass. Then, you need to use the mole ratio between CH4 and NH3 to find the number of ammonia molecules in the given amount of CH4. The mole ratio for CH4 to NH3 is 1:3, as 1 molecule of CH4 produces 3 molecules of NH3 in the balanced chemical equation.
The formula for methane is CH4, showing that each molecule contains exactly 5 atoms. Therefore, the number of atoms in 0.650 ml is 5 X 0.650 X Avogadro's Number, or about 1.96 X 1024 atoms, to the justified number of significant digits.
To calculate the number of molecules in 21.6 grams of CH4, you need to first determine the molar mass of CH4 (methane). The molar mass of CH4 is approximately 16 g/mol. Next, divide the given mass (21.6 g) by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
It represent a one molecule.CH4 stands for Methane
To find the number of ammonia molecules in 3.75g of CH4, you first need to convert 3.75g of CH4 to moles using the molar mass. Then, you need to use the mole ratio between CH4 and NH3 to find the number of ammonia molecules in the given amount of CH4. The mole ratio for CH4 to NH3 is 1:3, as 1 molecule of CH4 produces 3 molecules of NH3 in the balanced chemical equation.
The formula for methane is CH4, showing that each molecule contains exactly 5 atoms. Therefore, the number of atoms in 0.650 ml is 5 X 0.650 X Avogadro's Number, or about 1.96 X 1024 atoms, to the justified number of significant digits.
To react completely with one molecule of methane (CH4), two molecules of oxygen (O2) are needed. This is because the balanced chemical equation for the combustion of methane is CH4 + 2O2 → CO2 + 2H2O. Each molecule of methane requires two molecules of oxygen to form carbon dioxide and water.
There are one hundred 10g in 1kilo
To calculate the number of molecules in 21.6 grams of CH4, you need to first determine the molar mass of CH4 (methane). The molar mass of CH4 is approximately 16 g/mol. Next, divide the given mass (21.6 g) by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
No, they do NOT contain the same number of particles (either molecules N2 or atoms C): there molecular or atomic mass is different.Look at this:10g N2 / 28 (g/mole N2) x 6.022x1023 (molecules N2/mole N2) = 2.15 x1023 molecules N210g C / 12 (g/mole C) x 6.022x1023 (atoms C/mole C) = 5.02 x1023 atoms C
Ammonia (NH3) and methane (CH4) are not soluble in each other because they are both nonpolar molecules. Nonpolar molecules like these do not mix well with polar molecules like water, which is needed for molecules to dissolve in each other.
There are no molecules.Five atoms can be found.
20 x 500 mg = 10g or 10g = 500mg x 20