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How many molecules of CH4 are in 48.2 of this compound?
To determine the number of molecules in 48.2 g of CH4, you first convert the mass to moles using the molar mass of CH4 (16 g/mol). Then, since 1 mole of CH4 contains 6.022 x 10^23 molecules (Avogadro's number), you can calculate the number of molecules present in 48.2 g of CH4.
How many molecules in 10 grams of methane?
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
Calculate the number of molecules given grams i.e how many molecules are there in 21.6 grams of CH4?
To calculate the number of molecules in 21.6 grams of CH4, you need to first determine the molar mass of CH4 (methane). The molar mass of CH4 is approximately 16 g/mol. Next, divide the given mass (21.6 g) by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many molecules are contained in 19.3 g of the CH4?
Divide given mass by molar mass.19.3/16 There are 1.02625mol in it.Then multiply it by 6.02 × 10 23
How many methane molecules of Ch4 have a mass equal to 3.20 grams?
One mole is equal to 6.022 x 1023 of anything. In this case, we are looking for molecules. So 1 mole=6.022 x 1023 molecules. We have 2.3 moles, so we want to know how many molecules are there. 2.3 mol CH4 x 6.022x1023 molecules CH4 / mol CH4 = 1.38x1024 molecules of CH4
How many atoms are there in 64.5 grams of methane?
Molecular mass of CH4 = 12.0 + 4(1.0) = 16.0 Amount of CH4 = 64.5/16.0 = 4.03mol 1mol of CH4 contains 6.02 x 1023 molecules (avogadro constant). Therefore 4.03mol of CH4 contains 4.03 x 6.02 x 1023 = 2.43 x 1024 molecules.
How many molecules of S8 would be necessary to obtain 1.000 g of S?
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules
How many molecules in 1 g of water?
3.345*10^23
What is the correct equation for one molecule of methane gas reacts with two molecules of oxygen gas to form one molecule of context gas and two molecules of water vapor?
CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (g)
How many molecules of H2O are there in 1.0 g of H2O?
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
How many hydrogen atoms are there in 3.50 grams of methane?
3.5 g CH4 x 1 mole/16 g x 6.02x10^23 molecules/mole x 4 H atoms/molecule = answer.
How many grams of CO2 are formed for every gram of CH4 that combusts?
The balanced equation for combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2OThus, one mole CH4 produces 1 mole CO21 g CH4 x 1 mole CH4/16 g = 0.0625 moles CH40.0625 moles CH4 ==> 0.0625 moles CO20.0625 moles CO2 x 44 g CO2/mole = 2.75 g CO2Thus, the answer would be that 1 grams of CH4 will produce 2.75 grams of CO2 after complete combustion.
