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Using stoichiometry, 16.2 L of H2 gas at STP equals about .7228 moles (1 L of gas at STP has a volume of 22.41 L), and there are 6.02 x 1023molecules of hydrogen in a mole, so we have (6.02 x 1023molecules/mol)(.7228 mol) = 4.35 x 1023 hydrogen molecules. There are two hydrogen atoms in each molecule, so the answer is (4.35 x 1023molecules H2)(2 H atoms/molecule) = 8.70 x 1023 H atoms in 16.2 L.
- molar mass: 34,08 g- density: 1,363 g/cm3Mass of H2S: 1,363 x 9,36 = 12,758 g34,08--------------------------1 mol12,758-------------------------xx = 0,374 moles
The molar volume at 1 bar and 0 0C is 22,710 980(38) L/mol; each mol contain 6,022 140 857.10e23 molecules.
0.0710 mol
The answer is 0,2675 moles.
The answer is 8,5379.10e23 molecules.
Using stoichiometry, 16.2 L of H2 gas at STP equals about .7228 moles (1 L of gas at STP has a volume of 22.41 L), and there are 6.02 x 1023molecules of hydrogen in a mole, so we have (6.02 x 1023molecules/mol)(.7228 mol) = 4.35 x 1023 hydrogen molecules. There are two hydrogen atoms in each molecule, so the answer is (4.35 x 1023molecules H2)(2 H atoms/molecule) = 8.70 x 1023 H atoms in 16.2 L.
You need the balanced chemical reaction equation :------------------------------------------------------------------------2 K + 2 H2O ----. 2 KOH + H2moles H2 = n H2 = ( 1.60 L ) ( 1 mol H2 / 22.4 L H2 ) = 0.07143 moles H2moles K = n K = ( 0.07143 mol H2 ) ( 2 mol K / 1 mol H2 ) = 0.14286 moles Kmass K = m K = ( 0.14286 mol K ) ( 39.10 g K / mol K )mass K = m K = 5.56 g of potassium
- molar mass: 34,08 g- density: 1,363 g/cm3Mass of H2S: 1,363 x 9,36 = 12,758 g34,08--------------------------1 mol12,758-------------------------xx = 0,374 moles
The molar volume at 1 bar and 0 0C is 22,710 980(38) L/mol; each mol contain 6,022 140 857.10e23 molecules.
The mass of O2 is approximately 32.00g/mol. The mass of H2 is about 2.016g/mol. These masses can be obtained by using the atomic weights of the atoms that make up these molecules.
7.1g N2 (1mol N2/ 28.02g N2)(3 mol H2/ 1 mol N2)(2.0158g H2/ 1 mol H2) = 1.5 g H2
0.0710 mol
The chemical reaction is:N2 + 3 H2 = 2 NH3For six molecules of nitrogen N2 18 molecules of hydrogen H2 are needed.
The molar mass of H2 = 2.0159 g/mol
1 mole H2 = 2.016g H2 = 6.022 x 1023 molecules H210g H2 x 1mol H2/2.016g H2 x 6.022 x 1023 molecules H2/1mol H2 = 3 x 1024 molecules H2 (rounded to 1 significant figure)
0.00922 g of H2 gas will occupy approximately 0.100 L at STP