How many moles of argon gas are present in 5.6 liters of argon gas at standard conditions?

Answer 1

Well every mole of gas takes up 24 dm cubed. This is 24000 cm cubed - 2.4 litres. I would assume 5.6/2.4 would give your your answer (2.3 ish)

Answer 2

The volume of argon gas is 746 L.

Use the equation for the ideal gas law:

PV = nRT,

where:

P is pressure, V is volume, n is moles, R is the gas constant (varies with units), and T is temperature in Kelvins.

First you need to convert temperature from Celsius to Kelvins by adding 273 to the Celsius temperature: 175 C + 273 = 448 K.

Next you need to convert mass argon (Ar) to moles. The molar mass of Ar is 39.948 g/mol.

Mole Ar = 20.0 g Ar x (1 mol Ar)/(39.948 g Ar) = 0.50065 mol Ar (I am keeping a couple of extra digits to reduce rounding errors.)

Next look up the value for R.

R = 8.3144598 L kPa K-1 mol-1
https://en.wikipedia.org/wiki/Gas_constant

Solution

Rearrange the ideal gas law equation to isolate V. Plug in the known values and solve.

V=(nRT)/P

V Ar = (0.50065 mol Ar x 8.3144598 L kPa K-1mol-1 x 448 K)/(2.50 kPa) = 746 L Ar (rounded to three significant figures)

Answer 3

5 moles of argon contain 30,110704285.10e23 molecules.

Answer 4

The volume of argon is 746 L.