First write out the equation and balance it.
Then look at the ratio of C8H10 to CO2 produced in the reaction (hint: use molecular weights).
For example:
2A = 1B + 1C
where A =4, B=5, and C=3
so, for every 8g of A you get 5g of B
20g of B will yield 20 x 5/8 = 12.5g
18 grams H2O (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O molecules)
= 6.02 X 10^23 molecules of H2O
18/44 x 6.022x1023 = 2.464 x 1023 molecules
18g
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
A mole of water is about 18 grams or 18 milliliters of water.A mole of water has 6.022 x 10^23 water molecules. And 10.0 grams of has 3.345 × 10^23 water molecules. And there are 3 total atoms in water molecules, which is H2O. (3.34 × 10^23)*3=1.006 × 10^24 Which means that 1x10^24 atoms are in 10.0 grams of water.
A cup is 8 fluid ounces. And 8 ounces is about 236.6 grams of water.There are 18 grams of water in one mole of water, and a mole of anything contains Avogadro's number of molecules of that compound. That's 6.02 x 1023 molecules.Our (236.6 grams of water) divided by (18 grams per mole) = 13.14 moles of waterOur (13.14 moles of water)(6.02 x 1023 molecules per mole) = 7.91 x 1024 molecules in the 8 ounce glass of water.We had 8 ounces of water. We converted to grams. Then we looked up water to see how many grams of water there were in a mole of water. Then we found out how many moles we had in our cup of water. Then, because we knew how many molecules of water were in a mole (we know because a mole of anything is Avogadro's number of particles of that substance), we multiply to find out how many molecules of water were in the cup of water.That's how we found that there are 7.91 x 1024 molecules in a cup of water.
18 grams if sugar
That is 90 grams.
Each mole of a substance contains 6.022 E23 molecules or atoms of that substance. Four moles of H2O will contain 2.4088 E24 molecules.
After figuring out the calculations using the weight of CO2 and Avogadro's number, the total number of atoms in 110 grams of CO2 is 2.34 X 10^18 in sum.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
Each glucose molecule contains 6 carbon atoms. Thus we need 18 molecules of CO2 to make 3 molecules of glucose.
6,022.1023
18 grams
You would take your grams divided by the FW (formula weight) of the molecule. example: 1g of H2O divided by 18 = .056mol H2O you find the formula weight by adding of the atomic masses of each element O=16 and H=1 1(2)+16=18
18 pounds is 8164.66 grams.
18 kg = 18000 grams
A mole of water is about 18 grams or 18 milliliters of water.A mole of water has 6.022 x 10^23 water molecules. And 10.0 grams of has 3.345 × 10^23 water molecules. And there are 3 total atoms in water molecules, which is H2O. (3.34 × 10^23)*3=1.006 × 10^24 Which means that 1x10^24 atoms are in 10.0 grams of water.
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame
A cup is 8 fluid ounces. And 8 ounces is about 236.6 grams of water.There are 18 grams of water in one mole of water, and a mole of anything contains Avogadro's number of molecules of that compound. That's 6.02 x 1023 molecules.Our (236.6 grams of water) divided by (18 grams per mole) = 13.14 moles of waterOur (13.14 moles of water)(6.02 x 1023 molecules per mole) = 7.91 x 1024 molecules in the 8 ounce glass of water.We had 8 ounces of water. We converted to grams. Then we looked up water to see how many grams of water there were in a mole of water. Then we found out how many moles we had in our cup of water. Then, because we knew how many molecules of water were in a mole (we know because a mole of anything is Avogadro's number of particles of that substance), we multiply to find out how many molecules of water were in the cup of water.That's how we found that there are 7.91 x 1024 molecules in a cup of water.