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34.5 grams NaBrO3 (1 mole NaBrO3/150.89 grams)(6.022 X 10^23/1 mole NaBrO3)

= 1.38 X 10^23 molecules of sodium bromate

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13y ago
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11y ago

1 mole NaBr = 102.89377g

2.45mol NaBr x 102.89377g/mol = 252g NaBr

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Q: How many molecules of NaBrO3 are in a 34.5 gram sample of NaBrO3?
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