34.5 grams NaBrO3 (1 mole NaBrO3/150.89 grams)(6.022 X 10^23/1 mole NaBrO3)
= 1.38 X 10^23 molecules of sodium bromate
1 mole NaBr = 102.89377g
2.45mol NaBr x 102.89377g/mol = 252g NaBr
The number of molecules is 6,3985.10e24.
There are 1.5 moles water in 27 grams
1.64×1022 molecules
2.05×1022 molecules
The number of water molecules is 16,728.10e23.
The number of molecules is 6,3985.10e24.
There are 1.5 moles water in 27 grams
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
85.2 gram LiF sample is equivalent to 3,28 moles.
The number of molecules is 4,015.10e23.
The number of molecules is 4,015.10e23.
1.64×1022 molecules
A 22.5 gram sample of ammonium carbonate contains 4.5 moles of ammonium ions.
The number of water molecules is 16,728.10e23.
2.05×1022 molecules
1.51 x 10 ^23 molecules
The answer is 1,357.10 ex.23 molecules.