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How many molecules of S8 would be necessary to obtain 1.000 g of S?
Wiki User
∙ 8y ago
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules
Wiki User
∙ 8y ago
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he zero isn'treally necessary. that would be 2x1/10+5x1/100+3x1/1000 Thanks.
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