How many molecules of any gas at STP occupy a volume of 22.41 Liters?

Answer 1

We use, PV =nRT.

(1 atmosphere)( 44.8 L) = n(0.08206 L*atm/mol*K)*(298.15 K)

44.8/24.4662

= 1.831 moles of said gas

---------------------------------------now,

1.831 moles of said gas (6.022 X 1023/1 mole said gas)

= 1.10 X 1024 molecules of said gas

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Answer 2

Avogadro's Law (Avogadro's theory; Avogadro's hypothesis) is a principle stated in 1811 by the Italian chemist Amedeo Avogadro (1776-1856) that "equal volumes of gases at the same temperature and pressure contain the same number of molecules regardless of their chemical nature and physical properties". This number (Avogadro's number) is 6.022 X 1023. It is the number of molecules of any gas present in a volume of 22.41 L and is the same for the lightest gas (hydrogen) as for a heavy gas such as carbon dioxide or bromine.

Answer 3

Gas has the common formula of C8H18. This gives it a molar mass of 114.229 grams per mole, so there are 276 moles. This is equal to 1.662 E26 molecules.

Answer 4

1 mole or 6.023 * 10^23 numbers of molecules are present.

Answer 5

at STP 1 mole occupies 22.4 litres.

64.28 / 22.4 is 2.8696428 moles. Multiply this by avagadro's constant (6.022*10^23) gives 1.7281x10^24 molecules

Answer 6

There are 2 moles of oxygen if conditions are S.T.P

Answer 7

1 mole occupies 22.4 liters at STP so 44.8/22.4 = 2 moles so 2 x 6.022 x 1023 so 12.044 x 1023 or 1.2044 x 1024

Answer 8

44.8 L of oxygen gas into moles