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Answered 2012-01-23 12:09:44

no. of moles = mass in g/mass of one mole

no. of moles = 28.52/174.3

no. of moles = 0.16363 mol (rounded)

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How many moles of ions are in 2.70 mol of K2SO4


K2SO4 ==> 2K^+ and SO4^2- ions. So, each mole of K2SO4 produces 3 moles of ions.2.40 moles K2SO4 x 3 moles ions/mole K2SO4 = 7.2 moles of ions.


10.0 moles K2SO4 (6.022 X 1023/1 mole K2SO4) = 6.02 X 1024 atoms of potassium sulfate ==========================


Multiple the moles of K2SO4 by the molecular weight of 174.2592 grams. That should equal 210.85 grams.



There are 2 moles of cations (K+, potassium ion) in one mole K2SO4 So: 2*1.60= 3.20 moles cations


Molarity = moles of solute/Liters of solution ( 100 mL = 0.1 Liters)Moles of solute (K2SO4) = Liters of solution * MolarityMoles K2SO4 = 0.1 Liters * 0.1 M= 0.01 moles K2SO4 (174.27 grams/1 mole K2SO4)= 1.7 grams potassium sulfate=======================Add that many grams potassium sulfate to your 100 mL.



Potassium sulfate has a molar mass of 174.259 grams per mole. In15 grams there are then 86.1 millimoles of K2SO4.


2.60 moles There are 2 moles of K in K2SO4. the total moles times two (1.3 x 2) is 2.60 moles.


Since the product, K2SO4 has twice as many potassium atoms as the reactant, KNO3, we may conclude that it takes two moles of reactant to produce one mole of product. The sulfate and nitrate ions will not be the limiting factor.


2 KOH + H2SO4 = K2SO4 + 2 H2O 1 mole KOH, 1 mole H2SO4


So you said 1.81 mol n(K2SO4)=1.81 where K2SO4-> 2K+ + SO4 2- So the ratio is 1:2:1 so there are 0.905mol 2K+ and 1.81 mol SO4 2- hope that helps


A cation is the positive ion part of the ionic compound. That means for every mole of potassium sulfate, there are two moles of the cation potassium. So there are 2.90 moles of K+.


4.3 X Avogadro's Number, or 2.6 X 1024 molecules (to the justified number of significant digits).


There is 1 sulfur atom in potassium sulfate (K2SO4).


A fair question and some tricky points. Firstly, K2SO4 can be seen as 2K+[SO4]. If you put it into water, you get 2 potassium ions for each K2SO4. That's important. The rest is just wrestling with the numbers. We have 200cm3 of 2.0M K2SO4. How many moles is that? Well we'd have 2 moles in 1000cm3, so... (1000/200 = 5) we have 5 times less volume meaning 5 times fewer moles (2.0/5 = 0.4) so we have 0.4 moles K2SO4. Good. Now we put that into 800cm3 of water. There's a trick, here! It's not 0.4 moles into 800cm3 water, because our 0.4moles are ALREADY in their own 200cm3 of water. So remember to add the volumes up, too. But this just makes things so much easier for us! Because we end up with 1 litre which is the volume component of the molarity unit. (M = g/dm3 or g/L, same thing) So it's 0.4 moles of K2SO4 in 1litre of water, meaning 0.4M K2SO4. Finally....we want K+ ions, not K2SO4. Remember we had two K+ ions for every K2SO4? 2 x 0.4 = 0.8. So our answer is: we have 0.8M K+ solution in the end.


The Calculation25ml = 0.025dm30.5M = 0.5 moles per dm30.5 mol dm-3 x 0.025dm3 = 0.0125 moles of K2SO4Which equals 0.01125 moles of KThis in grams is 0.01125 x 39.098 (the molar mass of potassium) = 0.4398525g


In the K2SO4 equation, SO4 is not a cation since it consists of negatively charged ions. So K+ is the only cation, and since there are two of them then it is 2 mole K+ per mole K2SO4 . So 2 x 1.55 = 3.10 mol K+


Potassium sulfate (K2SO4)


K2SO4 is not soluble in acetone.


Is K2SO4 aqueous or solid



K2SO4 is the chemical formula for Potassium sulfate.


Molar mass of K2SO4 = 174.2592 g/mol



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