2 g HCl are equivalent to 0,0548 moles.
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
4 mole cuO X 2/1 = 8 mole Hcl
4 mole cuO X 2/1 = 8 mole Hcl
This reaction?2Al + 6HCl -> 2AlCl3 + 3H2Get moles species.60.0 grams Al (1 mole Al/26.98 grams) = 2.2239 mole Al==================================================================================2.2239 moles Al (6 mole HCl/2 mole Al)= 6.6717 moles HCl-------------------------0.68572 moles HCl (2 mole Al/6 mole HCl)= 0.22857 mole Al------------------------As you see you have way more moles aluminum than you need, but. you do not have nearly enough HCl to meet the mole burden.Hydrochloric acid limits this reaction.
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
FeS + 2HCl >> FeCl2 + H2S 75 grams FeS (1mole FeS/87.92 grams)(2 mole HCl/1 mole FeS) = 1.71 moles HCl 2 Molar HCl = 1.71 moles HCl/Liters = 0.855 Liters HCl, or as asked for; 855 milliliters of hydrochloric acid needed
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl
4 mole cuO X 2/1 = 8 mole Hcl
4 mole cuO X 2/1 = 8 mole Hcl
This reaction?2Al + 6HCl -> 2AlCl3 + 3H2Get moles species.60.0 grams Al (1 mole Al/26.98 grams) = 2.2239 mole Al==================================================================================2.2239 moles Al (6 mole HCl/2 mole Al)= 6.6717 moles HCl-------------------------0.68572 moles HCl (2 mole Al/6 mole HCl)= 0.22857 mole Al------------------------As you see you have way more moles aluminum than you need, but. you do not have nearly enough HCl to meet the mole burden.Hydrochloric acid limits this reaction.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
987 grams of Ra(OH)2 is equivalent to 3,78 moles.