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How many grams of zinc can react with 225ml of 0.200 m HCl solution?
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
What is the molarity of a solution of 73 g of HCL in 2 liters of water?
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
A chemist reacts 30.0 mL of 5.6 M HCl with an excess of Mg(OH)2. How many grams of magnesium chloride will be produced?
The reaction between HCl and Mg(OH)2 produces MgCl2 and water. Using stoichiometry, we find that 1 mole of MgCl2 is produced for every 2 moles of HCl. Calculate the moles of HCl reacted, then use the mole ratio to find the moles of MgCl2 produced. Finally, use the molar mass of MgCl2 to convert moles to grams.
How many grams of CaCl2 can be obtained if 14.6 g HCl is allowed to react with excess CaCO3?
The balanced chemical equation for the reaction between HCl and CaCO3 is: 2HCl + CaCO3 → CaCl2 + H2O + CO2. The molar ratio between HCl and CaCl2 is 2:1. Calculate the number of moles of HCl from 14.6 g, then use the mole ratio to find the moles of CaCl2. Finally, convert moles of CaCl2 to grams.
How many grams of HCL needed to react with 4000 g of Na2co3?
The balanced chemical equation for this reaction is 2 HCl + Na2CO3 -> 2 NaCl + H2O + CO2. From the equation, 1 mole of Na2CO3 reacts with 2 moles of HCl. Calculate the number of moles of Na2CO3 in 4000g, then use the mole ratio to find the moles of HCl needed. Finally, convert moles of HCl to grams.
How many moles of HCl and needed to react 2.4 moles of Al?
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
How many millimeters of a 2 Molar solution of hydrochloric acid are needed to completely react with 75 grams of iron sulfide?
FeS + 2HCl >> FeCl2 + H2S 75 grams FeS (1mole FeS/87.92 grams)(2 mole HCl/1 mole FeS) = 1.71 moles HCl 2 Molar HCl = 1.71 moles HCl/Liters = 0.855 Liters HCl, or as asked for; 855 milliliters of hydrochloric acid needed
How many grams of zinc can react with 225ml of 0.200 m HCl solution?
Balanced equation first.Zn + 2HCl - ZnCl2 + H2now we find moles HCl by....Molarity = moles of solute/Liters of solution ( 225 ml = 0.225 Liters )0.200 M HCl = X moles/0.225 Liters= 0.045 moles HCl================Now, drive reaction backwards.0.045 moles HCl (1 mole Zn/2 mole HCl)(65.41 grams/1 mole Zn)= 1.47 grams zinc reacted----------------------------------
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
What is the molarity of a solution of 73 g of HCL in 2 liters of water?
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
A chemist reacts 30.0 mL of 5.6 M HCl with an excess of Mg(OH)2. How many grams of magnesium chloride will be produced?
The reaction between HCl and Mg(OH)2 produces MgCl2 and water. Using stoichiometry, we find that 1 mole of MgCl2 is produced for every 2 moles of HCl. Calculate the moles of HCl reacted, then use the mole ratio to find the moles of MgCl2 produced. Finally, use the molar mass of MgCl2 to convert moles to grams.
How many grams of CaCl2 can be obtained if 14.6 g HCl is allowed to react with excess CaCO3?
The balanced chemical equation for the reaction between HCl and CaCO3 is: 2HCl + CaCO3 → CaCl2 + H2O + CO2. The molar ratio between HCl and CaCl2 is 2:1. Calculate the number of moles of HCl from 14.6 g, then use the mole ratio to find the moles of CaCl2. Finally, convert moles of CaCl2 to grams.
How many grams of HCL needed to react with 4000 g of Na2co3?
The balanced chemical equation for this reaction is 2 HCl + Na2CO3 -> 2 NaCl + H2O + CO2. From the equation, 1 mole of Na2CO3 reacts with 2 moles of HCl. Calculate the number of moles of Na2CO3 in 4000g, then use the mole ratio to find the moles of HCl needed. Finally, convert moles of HCl to grams.
In the reaction Mg (s) plus 2HCl (aq) H2 (g) plus MgCl2 (aq) how many grams of hydrogen gas will be produced from 125.0 milliliters of a 6.0 M HCl in an excess of Mg?
First, calculate moles of HCl: 125.0 mL of 6.0 M HCl is 0.75 moles. Since the ratio of HCl to H2 is 2:1, this will produce 0.375 moles of H2 gas. Finally, convert moles to grams using the molar mass of hydrogen to find the mass of hydrogen gas produced.
How many grams in 2 moles of HCI?
A Mole is the molecular weight expressed in grams. So for example water H2O: the molecular weight of oxygen is 16 and hydrogen is 1 so the total molecular weight of water is 18 (16 for one atom of oxygen plus 2x1 for the two atoms of hydrogen). For HCl, the atomic weight of Cl is 35 and H is 1 so the total molecular weight is 36. So 1 Mole of HCl is 36 grams. If you have 2 moles, it would be 72 grams.
How many moles of CuO are needed to react with 4 moles of HCL?
The balanced chemical equation for the reaction between CuO and HCl is: CuO + 2HCl --> CuCl2 + H2O This equation shows that 1 mole of CuO reacts with 2 moles of HCl. Therefore, to react with 4 moles of HCl, you would need 2 moles of CuO.
What is the mass of HCl that would be required to completely react with 5.2 grams of Mg?
The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.
