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1,8 grams of fluorine is equivalent to 0,0947 moles.
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
Number of moles is 9,8355/T (T in kelvin).
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
The answer is two moles of F atoms or 1 mole of F2 molecules.
One: The formula for magnesium fluoride is MgF2. Since each mole of fluorine molecules, which have the formula F2, contains two moles of fluorine atoms, one mole of each is the right ratio.
1,8 grams of fluorine is equivalent to 0,0947 moles.
19.2 moles
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
.298 Moles
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
0,25 moles F2
1.50 x 10 to the 23 atoms of fluorine is equal to 0,249 moles.
Number of moles is 9,8355/T (T in kelvin).
There is 19g of fluorine. That makes 1 mole.
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.