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The formula weight of NaCl is 58.44 which means 58.44 g = 1 mole.
Since 1000 mg = 1 g, this gives
58.44 g/mole x 1000 mg/g = 5.844 E+4 mg/mole.
Then, 52.1 mg NaCl x 1 mole NaCl/5.844E+4 mg = 8.92 E-4 mole.
See, this is just done by using the definitions of the units and the factor label method to analyze the conversion.
What else can I help you with?
How many moles of ions are in 2.5 mol of NaCl?
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
How many grams are in NaCl with 2.34 moles of Cl2?
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
How many grams of chlorine gas Cl2 are given off if 7.5 grams of sodium chloride NaCl are decomposed?
To determine how many grams of chlorine gas (Cl₂) are produced from the decomposition of sodium chloride (NaCl), we start with the balanced chemical equation for the reaction: 2 NaCl → 2 Na + Cl₂. From the molar mass of NaCl (approximately 58.44 g/mol), 7.5 grams of NaCl corresponds to about 0.128 moles. According to the stoichiometry of the reaction, 2 moles of NaCl produce 1 mole of Cl₂, so 0.128 moles of NaCl would yield 0.064 moles of Cl₂. The molar mass of Cl₂ is approximately 70.90 g/mol, resulting in about 4.54 grams of Cl₂ being produced.
How many moles of Na Cl could be made by combining 20000 mole of Na with 2 moles of Cl?
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
How many moles of ions are in 1.5 mol of NaCl?
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
How many moles of NaCl is 43.83grams of NaCl?
1 mole of NaCl: Na = 1 * 22.99 g = 22.99 g Cl = 1* 35.45 g = 35.45 g Total = 58.44 g 238 g NaCl * (1 mol NaCl/58.44 g NaCl) = 4.07 mol NaCl There are approximately 4.1 moles in 238 grams of sodium chloride.
How many moles of Na plus ions are there in a moles of NaCl?
There is one mole of Na⁺ ions for every mole of NaCl. This is because each mole of NaCl dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions in solution.
How many moles of NaCl are in 56.0 grams of NaCl?
The answer is 0,96 moles.
100ml of 0.200 molL NaCl is mixed with 400ml of 0.200 molL NaCl What is the concentration of Cl in the resulting solution?
The total moles of NaCl in the solution is 0.2 mol/L * (0.1 L + 0.4 L) = 0.3 moles. Since NaCl dissociates into 1 Na+ ion and 1 Cl- ion, the total moles of Cl- ions is also 0.3 moles. The concentration of Cl- ions in the resulting solution is 0.3 moles / (0.1 L + 0.4 L) = 0.6 mol/L.
What is the molarity of Cl- in 0.220M NaCl?
It is 0.22M also. moles refers to an amount of molecules OR atoms (i.e. ions)
How many moles of NaCl?
To determine the number of moles of NaCl, you need to know the mass of NaCl you have and the molar mass of NaCl (58.44 g/mol). You can then use the formula moles = mass / molar mass to calculate the number of moles of NaCl.
How many moles are there in 452g of NaCl?
The answer is 7,73 moles.
