ask youre teacher he knows do youre own work i was just tryin to do the same thing
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
Dilute 400ml of concentrated solution (14.8 M, 28% NH3) to 1 litre.
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
8.0 g according to my teacher but i dont know the formula
Dilute 400ml of concentrated solution (14.8 M, 28% NH3) to 1 litre.
2/5 of 1L = 400ML
1L = approx 1Kg therefore 1ml = 1g so 400ml = 400g
400mL is 13.5 (13.5256) fluid ounces.
it's 4dl
5/4
1000mL = 1L For every 1000mL we have 1 L. So- 400mL x 1L/1000mL = 0.4L
FROM: books.google.com/books?isbn=0702021172...ingested fluids = 1500mL/24hours water in food = 500mL/24hours metabolic water resulting from oxidation of food amounts = approximately 400mL/24hours
400ml
That is one fifth.