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ask youre teacher he knows do youre own work i was just tryin to do the same thing

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3mo ago

The total moles of NaCl in the solution is 0.2 mol/L * (0.1 L + 0.4 L) = 0.3 moles. Since NaCl dissociates into 1 Na+ ion and 1 Cl- ion, the total moles of Cl- ions is also 0.3 moles. The concentration of Cl- ions in the resulting solution is 0.3 moles / (0.1 L + 0.4 L) = 0.6 mol/L.

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Q: 100ml of 0.200 molL NaCl is mixed with 400ml of 0.200 molL NaCl What is the concentration of Cl in the resulting solution?
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