Will have to make some assumptions with the little info given.
Solid sucrose is 1.587 g/ml in density and has a mass of 342.30 grams/mole
Density = grams/milliliters
1.587 g/ml = grams/250 ml
= 396.75 grams/342.30 grams
= 1.159 moles of sucrose
Use the formula n=cv, you're given the "c", which is the concentration and the "v", which is the volume. Plug in these values into the equation and find "n".
*Remember to convert the volume into litres for this formula
Molarity = moles of solute / liters of solution
moles = Molarity x liters = 0.150 x .250 = 0.0375 moles
n (no. of moles)= Mass in 'g'/ Molar mass
= 250/ 180.156
= 1.388 mol
250.0 ml of water contain 13,9 moles.
The number of atoms is 2,167 970 708 52.10e25.
Glucose? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles water from one mole sugar.
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
10*(1/6)=1.67
Glucose is C6H12O6. So there are 6 carbons (C), 12 hydrogens (H) and 6 oxygens (O).
The number of moles is 2,997.
The number of atoms is 2,167 970 708 52.10e25.
0.67 moles of C6H12O6
Do you mean this reaction? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles oxygen required. --------------------------------
glucose 1 mole has 180,156 grams and has 6.022 x 1023 atoms carbon 1 mole has 12,01 grams and has 6.022 x 1023 atoms. There are 6 carbon atoms in a glucose molecule so that times six would give you a total of 72,06 grams out of the 180,156. Carbon makes up about 40 percent of the total glucose mass so the final answer would be it would be around 2.4088 x 1023 atoms of carbon in one gram of glucose.
10*(1/6)=1.67
Glucose? C6H12O6 + 6O2 -> 6CO2 + 6H2O 6 moles water from one mole sugar.
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
15.8 grams of C6H12O6 is equivalent to 0.087 moles.
5.60 g C6H12O6 (1 mole C6H12O6/180.156 g)(6 moles C/1 mole C6H12O6)(6.022 X 1023/1 mole C) = 1.12 X 1023 atoms of carbon ======================
Glucose is C6H12O6. So there are 6 carbons (C), 12 hydrogens (H) and 6 oxygens (O).
C6H12O6 Glucose has twelve hydrogen atoms